Compare two files


 
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# 1  
Old 03-21-2008
Compare two files

Kindly please assit me to compare two files in perl or any other script:


I have two files:

File1.abc

start prog
name cadillac
ggg abc
ttt fff

start prog
name Toyota
ggg abc
ttt fff

start prog
name Ford
ggg abc
ttt fff


File2.bcd

start apps
name mazda
ggg abc
ttt fff


start prog
name cadillac
ggg abc
ttt fff

start prog
name Toyota
ggg abc
ttt fff


start prog
name Isuzu
ggg abc
ttt fff



I have tried sdiff and diff but the output brings all kind of junks. I am specifically need to
compare just the "name" field.


The script only look for match written next to name field and will create an output telling me unmatch in name field.

So output will say:

name Ford found in file1.abc not found in File2.bcd
name mazda found in file2.bcd not found in File1.abc
name Isuzu found in file2.bcd not found in File1.abc


Thanks and appreciate your help.
# 2  
Old 03-21-2008
using awk (linux + bash):
Code:
awk ' BEGIN {RS = ""; FS = "(\n)| ( )"}  # set the record separator as ""

        # save the first file name and 4th field of it in an array 
        NR == FNR {   seen[$4] = 1; prefile = FILENAME }

        # test if the $4 in second file existing in the array or not
        NR != FNR  {
          nextf = FILENAME;
          if( $4 in seen)   seen[$4] = 0
          else      
             print $4 " found in " nextf " not found in " prefile
        }

        # print the field in first file but not in the nextfile
        END {
          for( ix in seen){
            if( seen[ix] == 1)
              print ix " found in " prefile " not found in " nextf
          }
        }
       '  file.abc  file.def


.Aaron

Last edited by yunccll; 03-21-2008 at 06:25 PM.. Reason: fix an expression error! :-)
# 3  
Old 03-24-2008
Thanks, but I am getting error:

$ ./Compare2NCFiles
awk: syntax error near line 9
awk: illegal statement near line 9
awk: illegal statement near line 10
# 4  
Old 03-25-2008
Hi,

Try follow one, it should be ok for you!

Code:
sed -n '/^name/p' a | awk '{print $2}' | sort > a.t
sed -n '/^name/p' b | awk '{print $2}' | sort > b.t
for i in `comm -23 a.t b.t`
do
echo "$i" is in a but not in b
done
echo
for i in `comm -13 a.t b.t`
do
echo "$i" is in b but not in a
done
rm a.t b.t

# 5  
Old 03-25-2008
I am confused now, should I replace this code with previous "awk" code.
In the second code I don't see the file name.

Please assist.....


Thanks
# 6  
Old 03-25-2008
It assumes the files to compare are called a and b. It is self-contained, basically a demo of how you would solve this with the "comm" command and related utilities. (sed | awk should be refactored to a single command, and the backticks should probably be avoided; otherwise it's pretty much the textbook solution.)

If you have mawk or nawk or gawk, try yunccll's script with one of those instead.
# 7  
Old 03-26-2008
Thanks it is working perfect. Appreciate your help.
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