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# 8  
Old 02-02-2008
Okay, now I'm having another problem with my script.

If I type:

Code:
echo {12..18}

It will spit out:

12 13 14 15 16 17 18

However, my script looks like this:

Code:
echo "Input first set of nodes" 

read node1 # This is where you insert the string of numbers

result=`echo $node1 | sed -r -e 's/([0-9]+)-([0-9]+)[ ]*/{\1..\2} /g'`

echo $result

I was hoping when it echoed $result, that the numbers that were inclosed in brackets for example {12..18} would then be printed as "12 13 14 15 16 17 18". This is not so, it merely echoes "{12-18}". Is there anyway for me to get this to work?

Thanks again.
# 9  
Old 02-02-2008
Quote:
Originally Posted by Kweekwom
KevinADC,

Thanks for looking into it. I tried it and got this error:

sed: -e expression #1, char 32: invalid reference \2 on `s' command's RHS


Is there anymore info I can give you to make my situation more clear?

Thanks again.
Actually mine should have been:

Code:
sed -e 's/([0-9]+)(-)([0-9]+)/{\1..\3}/g' file

(\3 instead of \2) but it may still not have worked. Like I said, I am not a sed coder really, juts learn what I have to on occasion. Thought I would give it a shot though as I am trying to pick up on more sed and ksh and similar.
# 10  
Old 02-02-2008
Quote:
Originally Posted by drl
Hi.

The seds I have used do not do "in-place" processing by default. If they allow it, it's usually with the "-i" option.
Thanks for the correction. I really was not sure. sed is fairly new to me, trying to pick up on it in my spare time. I should have known though, in this regards sed and perl are very very similar, -e -i and etc, the regular expression syntax appears to be identical as well.
# 11  
Old 02-03-2008
Hi.
Quote:
Originally Posted by Kweekwom
... it merely echoes "{12-18}". Is there anyway for me to get this to work?

Thanks again.
You are welcome; use bash3 and eval for this:
Code:
#!/bin/bash3 -

# @(#) user1    Demonstrate eval.

# echo "Input first set of nodes"

# read node1 # This is where you insert the string of numbers
node1="12-18"

result=`echo $node1 | sed -r -e 's/([0-9]+)-([0-9]+)[ ]*/{\1..\2} /g'`

echo {1..5}

eval echo $result

exit 0

Producing:
Code:
% ./user1
1 2 3 4 5
12 13 14 15 16 17 18

The useful page at http://www.tldp.org/LDP/abs/html/index.html can help you through these questions ... cheers, drl
# 12  
Old 02-03-2008
Awesome! Thanks drl, it worked perfectly.

Hopefully I only have one more question now.

I do what you suggested, and I want to sort the output of "eval echo" numerically, so I do this:

Code:
#!/bin/bash3 -

# @(#) user1    Demonstrate eval.

# echo "Input first set of nodes"

# read node1 # This is where you insert the string of numbers
node1="435-437,476-492 70-72,76,80-86"

result=`echo $node1 | sed -r -e 's/([0-9]+)-([0-9]+)[ ]*/{\1..\2} /g'`

echo {1..5}

eval echo $result | sort -n

exit 0

But, it doesn't sort them numerically. Is there something I'm doing wrong that is causing this?

Thanks again in advance, and thanks for the link!
# 13  
Old 02-03-2008
Hi.

The result of the final echo is a single line, so it is already in the correct order as sort looks at it.

What exactly are you looking for? If you were doing this manually, how would you go about it?

Note that you have interspersed a comma (,) at places in the list ... cheers, drl
# 14  
Old 02-03-2008
Quote:
Originally Posted by drl
Hi.

The result of the final echo is a single line, so it is already in the correct order as sort looks at it.

What exactly are you looking for? If you were doing this manually, how would you go about it?

Note that you have interspersed a comma (,) at places in the list ... cheers, drl
I really don't know how I would go about it doing it manually.

I'm sorry, I didn't mean to have those comma's in there. Even with no comma's in the line, it still doesn't sort.

I guess I need to come at the whole thing from a different angle?

All I basically need it to do is take a list of numbers, like this:

435-437 70-72 76 80-86

and print the ranges and sort all of it numerically.

Smilie
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