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How to get files names passed to a script

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# 1  
Old 11-06-2007
How to get files names passed to a script
I need to get files names passed to a script. Here number of files passed may vary
like MyScript.ksh file1 file2 file3..... so on

I am writting script somthing like this

set -A Files

while (i<=$#)
do
File[i]=$i
let i=i+1
done

Is this correct way doing this. Is there any other way.
Please let me know

Thanks.
# 2  
Old 11-06-2007
Code:
for file in $@
do
    echo "$file"
done

# 3  
Old 11-07-2007
The simplest way :
Code:
set -A Files -- "$@"     # First file in Files[0]
set -A Files -- "" "$@"  # First file in Files[1]

Jean-Pierre.
# 4  
Old 11-08-2007
Thanks for your reply. This is really useful.
What I should do if want all parameter passed except first one in array.
Pls let me know.

Thanks
Unishiv
# 5  
Old 11-08-2007
A possible solution is to remove the first parameter before filling the array:
Code:
param1=$1
shift
set -A Files -- "$@"

Jean-Pierre.
# 6  
Old 11-08-2007
I am not clear that much, however what I've understood, you need to modify your program a little .........

set -A Files
let i=2
while (i<=$#)
do
File[i]=$i
let i=i+1
done
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