Shell Programming and Scripting

I want to add the delimiter in particular positions in one txt file.

My file is :

123450000000000testing
898983920202020testfil
.
.
.

1-5 -- after 5th position add ,
6-10 -- after 10th position add ,
11-7 -- like wise..

Expecting output is:

12345,0000000000,testing
89898,3920202020,testfil
.
.
.

I have used the below script , but it is taking more timing to my 2
lak records.

#!/bin/sh
while read le
do
p1=`echo $le | awk '{ print substr($0,1,5) }'`
p2=`echo $le | awk '{ print substr($0,6,10) }'`
p3=`echo $le | awk '{ print substr($0,11,7) }'`

echo "$p1,$p2,$p3>> out.txt
done < in.txt

Is there anyother way to process the above.?

Code:

sed "s/\(.\{5\}\)\(.\{10\}\)/\1,\2,/" file

awk ' { print "%s,%s,%s", substr($0,1,5), substr ($0,6,10), substr($0,11,7) }' inputfile > outputfile

in bash,

Code:

echo "${a:0:5},${a:6:5},${a:10:${#a}}"

if you have Python, here's an alternative

Code:

#!/usr/bin/python
for line in open("file"):
  print line[0:5] + "," + line[5:15] + "," +line[15:-1]

output:

Code:

12345,0000000000,testing
89898,3920202020,testfil

Thanks guys.