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spllting the string

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# 1  
Old 01-25-2007
spllting the string
Hi

I have string

"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs

I want to split this string into two parts...

var1="sdfhhs"
var2="shfdjhfhfjshfshfsjhf",dsfsafsfs

can somebody tell me how i can achive this using awk
# 2  
Old 01-25-2007
Code:
/home/jmcnama> cat filename
"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs
/home/jmcnama> awk -F, '{ print $1 }' filename | read var1
/home/jmcnama> echo $var1
"sdfhhs"
/home/jmcnama> awk -F, '{printf("%s,%s", $2,$3)}' filename |read var2
/home/jmcnama> echo $var2
"shfdjhfhfjshfshfsjhf",dsfsafsfs

or
Code:
echo '"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs' | awk -F, '{ print $1 }' | read var1
echo '"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs' | awk -F, '{printf("%s,%s", $2,$3)}' filename |read var2

# 3  
Old 01-25-2007
thanks for reply....but i dont now the number of fields.....it can be variable.....
\

can i do like in awk ...

say i have to get entire string form second field.....without calculating total number of fields
# 4  
Old 01-26-2007
Try...
Code:
$ cat filename
"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs
$ var1=$(cut -d, -f1 filename)
$ var2=$(cut -d, -f2- filename)
$ echo $var1
"sdfhhs"
$ echo $var2
"shfdjhfhfjshfshfsjhf",dsfsafsfs

# 5  
Old 01-26-2007
checkout this.

#! /usr/bin/bash
a=`awk -F "," '{print$1}' ir`
echo $a
b=`awk -F "," '{print$2,$3}' ir`
echo $b

ir is the file name which contains the string
# 6  
Old 01-26-2007
Quote:
Originally Posted by mahabunta
I have string

"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs

I want to split this string into two parts...

var1="sdfhhs"
var2="shfdjhfhfjshfshfsjhf",dsfsafsfs
You can do it with shell variable expansion (without external commands):

Code:
$ str='"sdfhhs","shfdjhfhfjshfshfsjhf",dsfsafsfs'

$ str1="${str%%,*}"; echo "$str1"
"sdfhhs"

$ str2="${str#*,}"; echo "$str2"
"shfdjhfhfjshfshfsjhf",dsfsafsfs

# 7  
Old 01-26-2007
radoulov :

Could you please let me know what is that %% and # things represent. Could you please explain on those.

Thanks.
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