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awk: last occurance

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# 1  
Old 01-02-2007
Question awk: last occurance
Hi All,

I need to extract the last occurance of a pattern match. So far I've got the code below which extracts the first occurance. Any ideas how I can modify it so that it extracts the last?

Code:
BEGIN {}                        
{                               
   if (data[$2]++ == 0)         
      lines[++count] = $0       
}                               
END {                           
    for (i = 1; i <= count; i++)
        print lines[i]          
}

Thanks in advance,

p.
# 2  
Old 01-02-2007
could you paste an example what exactly you are looking for?
# 3  
Old 01-02-2007
how abt if you serach you pattern first and then use awk to print last line/last field?
Or
simply add your search algorithm in the statment section of awk instead of having it in BEGIN section. Not sure about your requirement but above are the possibilities as far as I could understand the question.

--Manish
# 4  
Old 01-02-2007
Quote:
Originally Posted by pondlife
Hi All,

I need to extract the last occurance of a pattern match. So far I've got the code below which extracts the first occurance. Any ideas how I can modify it so that it extracts the last?

Code:
BEGIN {}                        
{                               
   if (data[$2]++ == 0)         
      lines[++count] = $0       
}                               
END {                           
    for (i = 1; i <= count; i++)
        print lines[i]          
}

Thanks in advance,

p.
Code:
{  
   lines[$2] = $0                                 
}                               
END {                           
    for (i in lines)
        print lines[i]          
}

# 5  
Old 01-02-2007
Don't care about what i've said ... i've misred the original post
# 6  
Old 01-02-2007
Quote:
Originally Posted by becket
Don't care about what i've said ... i've misred the original post
hmmmmmm..... intersting - did you say anything on this thread at all?
# 7  
Old 01-02-2007
yes, but i've edited it
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