Shell Programming and Scripting

I have files with the names BARE01_DLY_MKT_20060724 in the source directory /biddf/ab6498/dev/ctl. I need to archive folders older than 30days. Like if i have a file named BARE01_DLY_MKT_20060622 I need to move this to /biddf/ab6498/dev/ctl/archive. How can I do this. One more thing is that I want to pass the file name namely BARE01_DLY as parameter to the script and it should see whether in the source directory there is a file oder than 30 days with that name and accrodingly move it to archive if it's older than 30days. Kindly help.

I have a similar question, because I don´t know any cammand that give me the creation date because all the commands I know give me the modify date.

If anyone know the solution I am very pleasent

All,

I will re-phrase my logic so that atleast somebody can give some logic.

I have files named BARE01_DLY_MKT_YYYYMMDD like wise for past 100 days in a direcotry /dev/bid/ctl.

I need to archive the files older than 30days in
/dev/bid/ctl/archive

Please suggest a method for this.

You can do something like this with find (non recursive form) :

Code:

cd /dev/bid/ctl
find . \( -type d ! -name . -prune  \) -o -name 'BARE01_DLY_MKT_*' -mtime +30 -exec mv {} archive/

Jean-Pierre.

Hi Jean,

I am getting this error. What does this mean?

find: -exec not terminated with ';'

The find command is incomplete :

Code:

cd /dev/bid/ctl
find . \( -type d ! -name . -prune  \) -o -name 'BARE01_DLY_MKT_*' -mtime +30 -exec mv {} archive/ \;

Jean-Pierre.

The problem is that find -mtime give us the modify not create time.