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Shell Programming and Scripting

Dollar symbol in Shell Script Variable

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# 8  
Old 09-21-2017
What we want to say is that --passphrase "abc$123" does NOT work as intended because it expands to --passphrase "abc${1}23" and if $1 is empty expands to --passphrase "abc23".
But
Code:
passphrase='abc$123'
... --passphrase "$passphrase"

works correctly. Maybe it does not work because your actual passphrase is abc23 ?
# 9  
Old 09-21-2017
Quote:
Originally Posted by Sreehari
Hi,

I am maintaining all keys in a file say ABC.pwdf

Contents of ABC.pwdf
================
Code:
<bank> <recipient> <signer> <passphrase>
WFB 0X12343 0x1234 abc$123

================

Reading these keys in shell script
=================
Code:
lnCount=0;
while read pString
do
	lvbank=`echo  ${pString}|cut -d ' ' -f1`

	if [ "$lvbank" = "$l_bank" ]``
	then		
		lnCount=`expr $lnCount + 1`
		recipient=`echo  ${pString} | cut -d ' ' -f2`;
		signer=`echo  ${pString} | cut -d ' ' -f3`;
		passphrase=`echo  ${pString} | cut -d ' ' -f4`;		
	fi;
done < ${PwdFileName};

======================
I am getting all values correctly. Having problem only when I am using passphrase in PGP command

Thanks,
Sreehari
For the third time, that is not all of your code. Now the bit with PGP in it is missing.

Post all your code.
# 10  
Old 09-21-2017
Thanks RudiC, I got the difference between harcoded value and variable. We decided to change passphrase without dollar sign.
# 11  
Old 09-25-2017
If your code - whatever it is - is evaluating dollar signs in passwords, that's a big problem. What if someone set their password to $(rm -Rf /var/importantdata) ?

Please show your code so we can find out why it's doing that.
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