If you might ever have cases where some of your script's arguments contain IFS characters, you'll need to use:
Code:
callme "$@"
instead of:
Code:
callme $*
And, note that processing arguments in a function (using local variables) makes those variables invisible to the calling script. If you intend to invoke callme and then use $file_in in your main script after callme returns; it won't work. (1st because your function exits instead of returning and 2nd because you're using local variables that do not exist outside the function.)
One might also wonder why you would have a utility that has one, and only one, option and that option is not optional, but is instead required to be present. Why not just treat it as an operand instead of an option? The then processing is much simpler:
Code:
#!/bin/bash
IAm=${0##*/}
if [ $# -eq 1 ]
then file_in="$1"
else printf 'Usage: %s filename\n' "$IAm" >&2
exit 1
fi
i am reading line by line from a file as below
while IFS= read -r var
do
...
...
...
done < "hello.txt"
I added the keytool command in the do while loop as below.
while IFS= read -r var
do
...
keytool -genkey -alias $fname -keyalg RSA -keystore $fname.jks -keysize 2048
...
done... (3 Replies)
I'm using getopts to process command line args in a Bash script. The code looks like this:
while getopts ":cfmvhs:t:" option; do
case $option in
c) operationMode="CHECK"
;;
f) operationMode="FAST"
;;
m) ... (6 Replies)
How can I say one of the options is required? can I use an if statement?
let say:
while getopts ":c:u:fp" opt; do
case $opt in
c) echo "-c was triggered, Parameter: $OPTARG" >&2;;
u) echo "-u was triggered, Parameter: $OPTARG" >&2;;
f) echo "-u was triggered,... (2 Replies)
i have the following scenario want to run the following script with manadory and optional argumnets
Manadory options are :
filename=""
port=""
optional arguments
type -t
balances -b bal
prices -p
./test filename port -t A -b bal
my code i have that won't parse the options is... (1 Reply)
Hello All,
I have shell script as below in a.ksh.
#! /usr/bin/ksh
while getopts a: b: ab:f: VAR
do
case $VAR in
a) A=${OPTARG}
echo $A;;
b) B=${OPTARG}
echo $B;;
ab) AB=${OPTARG}
echo $AB ;;
f) F=${OPTARG}
echo $F ;;
esac
done
When I execute sh a.ksh -a 1 -b 2 -ab 3 -f 4 as below... (7 Replies)
Hi, I'm having problems with a script where I wanted every single option specified in the command line to have an argument taken with it, but for some reason only d works in the code I will be showing below.
For example if I did ./thisfile -a something
it would come up with "a chosen with " as... (2 Replies)
Hi All,
How to enforce all users to change their password when they try to login.
I am having Solaris 9 and 10.
Even it would be much better if anyone can say to enforce all users to change their password next morning they login.
Thanks in advance,
Deepak (3 Replies)
Hi,
I need to implement something that will enforce login to a Solaris server as a particular, specifed user. After this login stage, users will be able to "su -" to whichever user they wish, by which time their activity will be captured by some sort of script (yet to be written). What I need... (7 Replies)
I need to create a shell script having the menu with few options such as
1. Listing 2. Change permissions 3. Modify Contents 4. Delete Files 5. Exit
1. For 1. Listing: Display a special listing of files showing their date of modification and access time (side by side) along with their... (2 Replies)
As a system administrator. sometimes we see the users are trying some commands dangerous for the system health and remove them from their individual coomand history file.
How it is possible to enforce that the normal usres will will not be able to modify the history.
Thanks in advance.
Partha (4 Replies)
