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Need to add a numeric & special char to end of the first line

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Top Forums Shell Programming and Scripting Need to add a numeric & special char to end of the first line
# 8  
Old 11-12-2016
Or more general (not needed here but useful in complex sed scripts)
Code:
sed -i '1s/$/'"$VAR"'/' file

Again the $var is in " " letting the shell expand it but not see+treat any special characters.
Of course the / delimiter in sed may not occur in the $var string, and no & character that is special in the replacement part of a sed substitution.
# 9  
Old 11-13-2016
Hi Don/MadeinGermany, I have already tried these, but they are giving me the below error.
Code:
sed -i "1s/$/$VAR/" Input_file
sed -i "1s/$/"$VAR"/" Input_file
sed -i '1s/$/"$VAR"/' Input_file
sed -i "1s/$/'"$VAR"'/" Input_file

Error:
Code:
sed: -e expression #1, char 20: unknown option to `s'

Is there a way in awk to get the below desired output, so that I will redirect the output to another file
Code:
12-11-16|11 2016 Jan 12:34:55|03:55|12-11-16|11 2016 Jan 12:34:55|03:55|
13-10-16|10 2016 Jan 12:34:55|03:55|12-11-16|11 2016 Jan 12:34:55|03:55|
14-10-16|19 2016 Jan 12:34:55|03:55|13-11-16|11 2016 Jan 12:34:55|04:55|
15-10-16|18 2016 Jan 12:34:55|03:55|14-11-16|11 2016 Jan 12:34:55|05:55|
16-10-16|17 2016 Jan 12:34:55|03:55|15-11-16|11 2016 Jan 12:34:55|06:55|
17-10-16|16 2016 Jan 12:34:55|03:55|16-11-16|11 2016 Jan 12:34:55|07:55|

# 10  
Old 11-13-2016
If all four of the commands:
Code:
sed -i "1s/$/$VAR/" Input_file
sed -i "1s/$/"$VAR"/" Input_file
sed -i '1s/$/"$VAR"/' Input_file
sed -i "1s/$/'"$VAR"'/" Input_file

are giving you the same output, you are not running these four commands!

What operating system are you using?

What shell are you using?

Please show us the exact output you get from running the following four commands:
Code:
set -xv
VAR="12-11-16|11 2016 Jan 12:34:55|03:55|"
sed -i "1s/$/$VAR/" Input_file
set +xv

# 11  
Old 11-13-2016
Hello Joselouis,

Could you please try following and let me know if this helps you.
Code:
awk -vvar="$VAR" 'NR==1{print $0 var;next} 1'  Input_file

Output will be as follows.
Code:
12-11-16|11 2016 Jan 12:34:55|03:55|12-11-16|11 2016 Jan 12:34:55|03:55|
13-10-16|10 2016 Jan 12:34:55|03:55|12-11-16|11 2016 Jan 12:34:55|03:55|
14-10-16|19 2016 Jan 12:34:55|03:55|13-11-16|11 2016 Jan 12:34:55|04:55|
15-10-16|18 2016 Jan 12:34:55|03:55|14-11-16|11 2016 Jan 12:34:55|05:55|
16-10-16|17 2016 Jan 12:34:55|03:55|15-11-16|11 2016 Jan 12:34:55|06:55|
17-10-16|16 2016 Jan 12:34:55|03:55|16-11-16|11 2016 Jan 12:34:55|07:55|

Also you could see in above code of awk have used -vvar="$VAR" which means in awk we have to define the shell variable values into awk's variables. You could re-direct this command's output to a temp_file and then could change it to Input_fie again. If you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk or nawk.

Thanks,
R. Singh
These 2 Users Gave Thanks to RavinderSingh13 For This Post:
Joselouis rbatte1
# 12  
Old 11-13-2016
Thank you R.Singh.. code has worked Smilie
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