Shell Programming and Scripting

hi ,
how can i print every character in new line on unix
i want to have abcd like this:

Code:

a
b
c
d

this code didn't worked in my os but worked on linux

Code:

echo "abcd"|  'sed 's/\(.\)/\1\n/g'

best reagard

Moderator's Comments:

Please use CODE tags as required by forum rules!

Wouldn't you think, too, that it helped if you told us WHAT your OS is on which that code didn't work? And, what your shell is, because that might offer an easy answer/solution as well...

UnixWare 7.1.4 and shell is csh

Hello rezasadeghi,

Please use code tags as per forum rules for your Input_file/code/commands which you are using into your code. Following is the rules link for same, you could go through it once.
https://www.unix.com/misc.php?do=cfrules

Coming to your requirement, could you please try following and let us know then.

Code:

awk '{A=A?A OFS $0:$0} END{print A}'  Input_file

NOTE: As per your Input_file only above command is provided, in case you have other requirements by which above output is not matching to your requirements, then please mention all the details about your requirements along with sample Input_file and expected output too, along with your O.S details etc.

Thanks,
R. Singh

my requirements :
print "abcd" like :
a
b
c
d
the solution of you didn't work

Showing us the exact diagnostics produced by your code when it doesn't work ALWAYS helps get a meaningful answer sooner.

Removing the extraneous unmatched single quote would probably help. Depending on what operating system and version of sed you're using, that might even fix your problem. But, probably not on UnixWare.

Try:

Code:

echo "abcd"|sed 's/./&\
/g'

where there is nothing but a <newline> character following the backslash at the end of the 1st line.

NOTE: With the extra single quote before sed in your script I can't believe that that worked on any system. I will not guarantee that the above will work with csh and its derivatives, but it should work with any shell based on Bourne shell syntax.

Hello rezasadeghi,

Sorry for that, didn't understand problem correctly. Following may help you in same.

Code:

 awk '{num=split($0, A,"");for(i=1;i<=num;i++){print A[i]}}'  Input_file

Also I have tried above command in GNU awk in BASH.

Thanks,
R. Singh