Add delimiter to a file from layout file


 
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# 8  
Old 05-16-2016
Quote:
Originally Posted by RudiC
Try this pure shell (bash):
Code:
while IFS="       (:)" read _ _ P _ _ L; do ((IX++)); POS[$IX]=$((P-1)); LEN[$IX]=$L; done < layout.txt

while read T
  do    unset CRS L
        for i in ${!POS[@]}
          do    L=$L${T:$CRS:$((${POS[$i]}-CRS))}"~"${T:${POS[$i]}:${LEN[$i]}}"~"
                CRS=$((${POS[$i]}+${LEN[$i]}))
          done
        L=${L#\~}
        L=${L//~~/\~}
        L=$L${T:$CRS}
        printf "%s\n" $L
  done < abc.txt
11~01~0116~03~15100000000000000
11~01~0116~03~15100000000000000

Thanks this looks perfect ,
when I run it in ksh it gives error for IX, I defined IX=0 but still doesn't work
Code:
IX++: bad number

any idea why ?

Last edited by RudiC; 05-16-2016 at 05:53 AM.. Reason: Added [i]code tags.
# 9  
Old 05-16-2016
ksh93 should know the arithmetic evaluation within (( ... )). What be your ksh version?

Replace the post increment command by any other that will increment IX by 1.
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