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Shell Programming and Scripting

Data manipulation, Please help..

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Top Forums Shell Programming and Scripting Data manipulation, Please help..
# 8  
Old 03-24-2016
OK, so that means create 1 - n lines numbered 1 - n, of 1 - n elements, but break each line at 4 elements, and repeat the line number in front of each broken sub line?
What if the count of input elements is less or more than 55, in above case?
# 9  
Old 03-24-2016
Quote:
Originally Posted by RudiC
OK, so that means create 1 - n lines numbered 1 - n, of 1 - n elements, but break each line at 4 elements, and repeat the line number in front of each broken sub line?
What if the count of input elements is less or more than 55, in above case?
It should be exact with 1+2+...+n, that says 55 for n=10 because it is generated by a quantum chemical calculation. If number of numbers are large than 55, then just neglect the numbers in the position beyond 55. Normally, again it should be exactly match. The hard problem for me is the break of each line at 4 when n > 4.
Thanks.
# 10  
Old 03-24-2016
Try
Code:
awk -F, -vn=10 '
        {for (i=1; i<=n; i++)   {printf "%s", i
                                 for (j=0; j<i; j++) printf "%s%+f", (j%4?"":j?ORS i:"") OFS, $(++c)
                                 printf RS
                                }
        }
' OFS="\t" file
1    +0.498766
2    -0.031608    +0.609925
3    +0.003612    +0.014010    +0.542741
4    -0.048814    -0.014547    +0.025696    +0.049521
5    -0.014581    -0.144680    +0.131557    +0.019123
5    +0.151256
6    +0.000000    +0.000000    +0.000000    +0.000000
6    +0.000000    +0.000000
7    +0.000000    +0.000000    +0.000000    +0.000000
7    +0.000000    +0.000000    +0.000000
8    +0.000000    +0.000000    +0.000000    +0.000000
8    +0.000000    +0.000000    +0.000000    +0.000000
9    +0.000000    +0.000000    +0.000000    +0.000000
9    +0.000000    +0.000000    +0.000000    +0.000000
9    +0.000000
10    +0.000000    +0.000000    +0.000000    +0.000000
10    +0.000000    +0.000000    +0.000000    +0.000000
10    +0.000000    +0.000000

This User Gave Thanks to RudiC For This Post:
liuzhencc
# 11  
Old 03-24-2016
Quote:
Originally Posted by RudiC
Try
Code:
awk -F, -vn=10 '
        {for (i=1; i<=n; i++)   {printf "%s", i
                                 for (j=0; j<i; j++) printf "%s%+f", (j%4?"":j?ORS i:"") OFS, $(++c)
                                 printf RS
                                }
        }
' OFS="\t" file
1    +0.498766
2    -0.031608    +0.609925
3    +0.003612    +0.014010    +0.542741
4    -0.048814    -0.014547    +0.025696    +0.049521
5    -0.014581    -0.144680    +0.131557    +0.019123
5    +0.151256

MAGIC!!!
Code:
(j%4?"":j?ORS i:"") OFS, $(++c)

This is the most difficult Part I never understand.. But it does the trick! Thanks so much for your help!
ZHen
# 12  
Old 03-24-2016
Try also this simplification:
Code:
awk -F, -vn=10 '
        {for (i=1; i<=n; i++)
           for (j=0; j<i; j++) printf "%s%+f%s", (j%4?"":(j?ORS:"") i) OFS, $(++c), (i-j-1)?"":ORS
        }
' OFS="\t" file

It's making intensive use of the so called "conditional operator" expr?expr:expr that, if the first expr evaluates to true, supplies the second's, else the third's result.
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