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Shell Programming and Scripting

Print Missing Header Name from File.

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# 1  
Old 03-14-2016
Print Missing Header Name from File.
HI Guys,

I have file A.txt

Code:
ID,L1,L2,L3,L4
1A,2a,33a,44b,55c
2A,10a,14a,15b,16c

File B.txt

Code:
ID
L1
L4
L5

Output:-

Code:
ID,L1,L4,L5
1A,55c,n/a
2A,16c,n/a

I have below solution which is works perfect if all header match from file b.

Code:
nawk -v OFS="," '$1=$1' $Lic1 > $Lic2

	nawk '
	BEGIN           {OFS = FS = ","}
	FNR == NR       {h[$0] = NR
                 MX = NR
                 next
                }
	FNR == 1        {for (i=1; i<=NF; i++) if ($i in h) a[h[$i]] = i
                }

                {for (i=1; i<=MX; i++) printf "%s%s", $a[i], (i==MX)?RS:OFS
                }
	' fileB fileA

Thanks
# 2  
Old 03-14-2016
Do not understand your request
Are you looking to determine the entries not specified?
return L2 and L3 ??
# 3  
Old 03-14-2016
Your output sample seems to miss the L1 column values. However, try
Code:
awk '
BEGIN           {OFS    = FS = ","}
FNR == NR       {H[$0]  = NR
                 HI[NR] = $0
                 MX     = NR
                 next
                }
FNR == 1        {for (i=1; i<=NF; i++) if ($i in H) A[H[$i]] = i
                }

                {for (i=1; i<=MX; i++) printf "%s%s",  (A[i]?$A[i]:(FNR==1)?HI[i]:"n/a"), (i==MX)?RS:OFS
                }
' file2 file1

This User Gave Thanks to RudiC For This Post:
pareshkp
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