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Shell Programming and Scripting

Delete word from the file

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Top Forums Shell Programming and Scripting Delete word from the file
# 8  
Old 08-28-2015
To get output in a file, put it in a file.

Code:
while something
do
...
done < file > outfile

# 9  
Old 08-31-2015
I've one last question.

With this code I can get a .txt file as required. However, I would like to get a fresh file everyday instead of the appending the the same .txt file.

Code:
#!/bin/sh
for i in "/usr/sas/sas_config/Lev1/SASApp/StoredProcessServer/Logs/SASApp_STPServer_"$(date +%Y-%m-%d --date "4 day ago")"_tmptcmsaslva2_"*".log"
do  
       echo "${i##*/}" < output_file.txt
done

e.g. If I run today I may get 3 records in output_file.txt. When I run tomorrow I should not get the same records along with current day's records in output_file.txt rather I should get only current day's records in output_file.txt
# 10  
Old 08-31-2015
Hello Ram,

There are two ways to complete this request.
I- Keep getting a output file which has particular day's date in it's name itself, so each day files will be unique and different names.
Code:
#!/bin/sh
DATE=`date +%y%m%d`
 for i in "/usr/sas/sas_config/Lev1/SASApp/StoredProcessServer/Logs/SASApp_STPServer_"$(date +%Y-%m-%d --date "4 day ago")"_tmptcmsaslva2_"*".log"
do  
       echo "${i##*/}" >>  "output_file_"$DATE".txt"
done

II- Each day check for file named output_file.txt and rename it to that's day's date and create a output file with name output_file.txt.
Code:
#!/bin/sh
DATE=`date +%y%m%d`
if [[ -f output_file.txt ]]
then
      mv output_file.txt "output_file_"$DATE".txt"
fi
for i in "/usr/sas/sas_config/Lev1/SASApp/StoredProcessServer/Logs/SASApp_STPServer_"$(date +%Y-%m-%d --date "4 day ago")"_tmptcmsaslva2_"*".log"
do  
       echo "${i##*/}" >>  output_file.txt
done

Thanks,
R. Singh
Last edited by RavinderSingh13; 08-31-2015 at 06:26 AM..
This User Gave Thanks to RavinderSingh13 For This Post:
Ram Kumar_BE
# 11  
Old 08-31-2015
There is other way which I found nowSmilie. Just I put a remove command at the beginning of the script like below.
Code:
#!/bin/sh
rm output_file.txt
for i in "/usr/sas/sas_config/Lev1/SASApp/StoredProcessServer/Logs/SASApp_STPServer_"$(date +%Y-%m-%d --date "1 day ago")"_tmptcmsaslva2_"*".log"
do
    echo "${i##*/}" >> output_file.txt
done

Now I'm looking to capture the script execution in log files (.log)
# 12  
Old 08-31-2015
Quote:
Originally Posted by Ram Kumar_BE
.
.
.
Code:
#!/bin/sh
for i in "/usr/sas/sas_config/Lev1/SASApp/StoredProcessServer/Logs/SASApp_STPServer_"$(date +%Y-%m-%d --date "4 day ago")"_tmptcmsaslva2_"*".log"
do  
       echo "${i##*/}" < output_file.txt
done

.
.
.
With this code snippet, you won't get any output_file.txt. Replacing < with > , you'd get an output_file.txt with exactly the last .log file name encountered.
Putting the > output_file.txt right after the done, as proposed by Corona688 in post#8, you'll have a new output file every time you run the snippet.
# 13  
Old 08-31-2015
Script is working fine. Earlier there was a line feed issue.

Now I was looking to get a script execution log file.
Last edited by Ram Kumar_BE; 08-31-2015 at 07:28 AM..
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