Shell Programming and Scripting

Hi all,

I am doing something like below:

Code:

MaxTime=$(bc <<< "scale = 3; ($MaxTime / 10)")

where MaxTime=127. I am getting answer as 12.700

Now I don't want to use bc. I want to do same thing without bc.

I am novice to shell scripting could anyone please tell me how to achieve same thing without using bc?

thanks
--girija

Hello girijajoshi,

Welcome to forums. Please use code tags for commands/codes/inputs you are using in your posts as per forum rules. You can try following on same.

Code:

 awk -vMAXTime=127 'BEGIN{printf "%.3f\n",MAXTime/10}'

Output will be as follows.

Code:

 12.700

Thanks,
R. Singh

In your example, the original value assigned to MaxTime is an integer. Will that always be the case, or can the original value be a floating point value?

What shell are you using? Can you use a 1993 or later version of the Korn shell? (It can perform floating point operations using shell arithmetic expansions.)

Do you just need to perform division by 10, or do you need to handle arbitrary arithmetic operations?

Hi Ravinder,

Thanks for the reply.

Code:

awk -vMAXTime=127 'BEGIN{printf "%.3f\n",MAXTime/10}'

the above code gives me the op. could you please tell me how to store the return value in the variable. So that I can use that value for further calculations.

thanks
--girija

Do it just like you did it in your first post in this thread:

Code:

MAXTime=$(awk -vMAXTime=127 'BEGIN{printf "%.3f\n",MAXTime/10}')

If you answer my earlier questions, there may be MUCH more efficient ways to do this.

Hello girijajoshi,

Please use code tags for commands/codes which you are using in your posts as per forum rules, here is the link for same too.
https://www.unix.com/misc.php?do=cfrules

You can store it in a variable as follows.

Code:

 VAR=`awk -vMAXTime=127 'BEGIN{printf "%.3f\n",MAXTime/10}'`

If you want to see variable's value do a echo $VAR.
Hope this helps.

Thanks,
R. Singh

Hi all,

Thanks for the response. Ravinder's thing helped me a lot.

thanks
--girija