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Remove Carriage Return (CRLF) within double quotes

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Top Forums Shell Programming and Scripting Remove Carriage Return (CRLF) within double quotes
# 8  
Old 07-24-2015
Then, try:
Code:
perl -0777 -pe 's/\n^(?!\d)/ /smg; s/(-- ) /$1/g' broken_cvs > fixed_cvs

# 9  
Old 07-24-2015
There seem to be no CRLF in your sample, only LF

Try:
Code:
awk 'NR%2-1{gsub(/\r?\n/, FS)} NR>1{printf RS}1' RS=\" ORS= file

Last edited by Scrutinizer; 07-24-2015 at 07:30 PM..
# 10  
Old 07-27-2015
Any body here? I need help.
# 11  
Old 07-27-2015
We have provided you with two more suggestions. We are waiting for you. Please post some feedback first.
# 12  
Old 07-27-2015
I got it, the following works
Code:
awk 'NR%2-1{gsub(/\r?\n/, FS)} NR>1{printf RS}1' RS=\" ORS= file

---------- Post updated at 11:04 AM ---------- Previous update was at 10:44 AM ----------

I want to further edit the file, there are some lines with LF within double quotes though all lines ends with CRLF. How do I get rid of LF.
Last edited by Scrutinizer; 07-27-2015 at 11:47 AM.. Reason: CODE tags
# 13  
Old 07-27-2015
I think your code handles LF within quotes well.
The only potential problem is a "line too long", if there is a sequence of many lines without quotes.
The following seems a bit complicated but avoids the problem
Code:
awk -F\" '(NF%2==0) {if (append) {append=0; print buf sep $0; next} else {append=1; buf=sep=""}} (append) {sub("\r$",""); buf=buf sep $0; sep=OFS; next} {print}'

Replace sep=OFS by sep=ORS if you want to remove the LF within quotes in a CRLF-delimited file (as you originally requested.)
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