Shell Programming and Scripting

As has been said several times before in this thread, you can't have spaces around the equal sign in a shell variable assignment.

Then you need to assign a value to the variable d (which I assume is intended to contain the pathname of your destination directory.

Assuming that you are trying to copy a single file to a new directory with a new name, you can only give two operands to cp; not three ($f (your source file), $d (presumably your destination directory), and "$(printf "%u" $num) . png" (which is a slow way to create a filename consisting of a number, a space, a period, a space, and the string png)).

You talked about having a base name for your files based on the final component of the pathname of your destination directory, but I don't see anything in your code that attempts to do that. There isn't anything that checks to see whether or not the calculated destination filename already exists either. Maybe you want something more like:

Code:

num=1
dp=/destination/directory/test
d=${dp##*/}
for f in *.png *.doc
do	while [ -e "$dp/$d$num.${f##*.}" ]
	do	num=$((num + 1))
	done
	cp -v "$f" "$dp/$d$num.${f##*.}"
	num=$((num+1))
done

This won't try to number .png and .doc files separately, but will verify that an existing file won't be overwritten by a new file being copied into the destination directory. (If you want separate numbering for the different file extensions, the easy way to do it would be to break the for loop into two for loops.