How to print N number of lines before and after the grep?


 
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Old 06-18-2015
Question How to print N number of lines before and after the grep?

Hi ,
My record file , need to print up to above (DATA array)(there may be n no lines ) , grep "myvalue" row now .....suggest me some options
Code:
--- DATA Array---
record type xxxxx
sequence type yyyyy
2
3---> data1 
/dev/
--- DEVICE ---
MAXIMUM_People=[SUB device ]
data_blocks=[GET details ]
MY_value=2
xyz
abc 
people =[xxxxxxxxxxxxx]


Last edited by Scott; 06-29-2015 at 02:10 PM.. Reason: Please use code tags
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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD