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Unable to set Global variable outside while loop

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Top Forums Shell Programming and Scripting Unable to set Global variable outside while loop
# 8  
Old 05-09-2015
Quote:
Originally Posted by mohtashims
In that case let me just post my case and what i m trying to do.

I m in a directory that has a few sub directories.

I need to grep for a string in all files in all sub directories starting with the sub directory with the latest time stamp.

If grep string is found i need to break off and stop the search [this is why i was using break].

If the desired string is not found I need to grep for the string in the other sub directories.

After the process completes I should display the results of the grep if the desired search string has been found in any of the files or else Display a message that "No records Found"

I hope you can give me an idea as my expertise did not help.
This leaves a few details to be explained: you effectively search for the first match in each subdirectory, yes? Or do you want to stop the search completely after the first found match?

Supposing it is the first, here is a sketch. Because your inoput was sketchy at best the script is, too. You will have to fill in some parts. Note that the search pattern might not work if it contains too much regexp. In this case you will have to report back:

Code:
typeset -i lFound=0
typeset    fDir=""
typeset    fFile=""
typeset    chSearch="<yoursearchpattern>"

<process producing list of dirs, one per line> |\
while read fDir ; do
     lFound=0
     ls "$fDir" | while read fFile ; do
          if [ lFound -eq 0 ] ; then
               grep "$chSearch" "${fDir}/${fFile}"
               if [ $? -eq 0 ] ; then
                    lFound=1
               fi
          fi
     done
done

I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
mohtashims
# 9  
Old 05-09-2015
Quote:
Originally Posted by mohtashims
In that case let me just post my case and what i m trying to do.

I m in a directory that has a few sub directories.

I need to grep for a string in all files in all sub directories starting with the sub directory with the latest time stamp.

If grep string is found i need to break off and stop the search [this is why i was using break].

If the desired string is not found I need to grep for the string in the other sub directories.

After the process completes I should display the results of the grep if the desired search string has been found in any of the files or else Display a message that "No records Found"

I hope you can give me an idea as my expertise did not help.
And the template I provided in post #4 in the thread Need Linux equivalent for UNIX did exactly that. It includes tested, working code (although it did make a lot of assumptions about things you left unspecified). Did you try starting with that template? What didn't work when you used that template?

And the command:
find * -prune -type d | sort -r -n
gives you directories in reverse alphabetic name order; not reverse order by modification time (assuming that your directory names start with "fd" as in your previous thread's example).
This User Gave Thanks to Don Cragun For This Post:
mohtashims
# 10  
Old 05-10-2015
Quote:
Originally Posted by Don Cragun
And the command:
find * -prune -type d | sort -r -n
gives you directories in reverse alphabetic name order; not reverse order by modification time
Don is right, i haven't even bothered to look at that. What's more, "sort -rn" sorts in reverse numerical order and for a list of directory names this is (usually) nonsense. Remove "-n" because it does nothing at best and not what you want at worst.

Sometimes, i'd like to add, it is a good idea to read the man pages. Not, because everybody keeps telling you that, but because reading these with the intention to understand them is the speed lane to not having to open such threads. With that amount of posts under your belt you should have learned at least the basics of script programming - if you ever had the intention to do so, that is.

I hope this helps.

bakunin
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