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What was wrong ??? ksh

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# 1  
Old 02-21-2006
What was wrong ??? ksh
I wrote this code and did not know what did I do wrong ??

## get the first line of this file
AFIRST=$(head -1 rss-cs-3423a-20051211-060001.dat)
#CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111 <--- this is a answer

## Third line of stat file
BTHREE=$(cat rss-cs-3423a-20051211-060001.stat | sed -n 3p)
#CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111
 <--- this is a answer, both of them the same

### Compare AFIRST and BTHREE
if [[ $AFIRST = $BTHREE ]];
then
print "First record is matched"
else
print "First record is not matched"
fi



====

Why I get the answer is The First Record is not matched ??? syntax error ?
Please help me Smilie
# 2  
Old 02-21-2006
Your syntax is fine, but if your two variables differ by just one space then they are not matched. Try putting in some debug statements just before your if statement, e.g.....

echo AFIRST=[$AFIRST]
echo BTHREE=[$BTHREE]
# 3  
Old 02-21-2006
No it has to do with the pipe "|" symbols in the strings.

It is confusing the test. I don't know a way around it though. I've tried it myself with double quotes and single quotes around the strings but it still fails.

Perhaps perl is capable or there is a test in ksh I am just not aware of.
# 4  
Old 02-21-2006
Quote:
Originally Posted by DogDay
No it has to do with the pipe "|" symbols in the strings.

It is confusing the test. I don't know a way around it though. I've tried it myself with double quotes and single quotes around the strings but it still fails.

Perhaps perl is capable or there is a test in ksh I am just not aware of.
Sorry, but I have to disagree entirely. Here is proof at the ksh prompt...
Code:
$ AFIRST="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
$ BTHREE="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
$ if [[ $AFIRST = $BTHREE ]]; then echo "First record is matched"; else echo "First record is not matched"; fi
First record is matched

# 5  
Old 02-21-2006
Quote:
Originally Posted by Ygor
Sorry, but I have to disagree entirely. Here is proof at the ksh prompt...
Code:
$ AFIRST="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
$ BTHREE="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
$ if [[ $AFIRST = $BTHREE ]]; then echo "First record is matched"; else echo "First record is not matched"; fi
First record is matched

And I get to disagree too!

Code:
# AFIRST="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
# BTHREE="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
# if [[ $AFIRST = $BTHREE ]]; then echo "First record is matched"; else echo "First record is not matched"; fi
First record is not matched

sabercats said he is using ksh, what flavor of ksh are we talking about?
# 6  
Old 02-21-2006
how about this:
Code:
> AFIRST="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
> BTHREE="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
> if [ ! -z $(echo $AFIRST | grep "$BTHREE") ]; then echo "First record is matched"; else echo "First record is not matched"; fi

# 7  
Old 02-21-2006
Very roundabout but it works.
Code:
# AFIRST="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
# BTHREE="CJKA|2005-12-10 08.01.30.000000|1111111111|ECI|1112221111|1113331111|1114441111"
# if [ ! -z $(echo $AFIRST | grep "$BTHREE") ]; then echo "First record is matched"; else echo "First record is not matched"; fi
First record is matched

And your grep for the BTHREE string in the AFIRST string will match any string that contains BTHREE within it. So its not a good test unless you are certain the data will never be out of those constraints.

Perhaps:

Code:
grep ^"$BTHREE"$
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