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Syntax error near unexpected token

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# 8  
Old 11-29-2014
Quote:
Originally Posted by Scrutinizer
Please do not leave people guessing. Be complete. Show a representative sample of input, desired output, attempts at a solution and specify what OS and version are being used.
Content of test.sh ;

Code:
#!/bin/bash
count=$((1))
while read item
  printf %s `sed -n $"count"p test1.txt` > test2.txt
  count=$((count+1))
  do     
  echo "why?"
done <test3.txt

I am just experimenting to investigate the behavior there is no purpose. Please find test1.txt and test3.txt in the attachment. I want to echo for the amount of line numbers in test3.txt but it doesn't quit the loop now.
test1.txt (1.0 KB) 
test3.txt (1.5 KB) 
# 9  
Old 11-29-2014
Show
  • a representative sample of input - check
  • desired output - missing
  • attempts at a solution - check
  • specify what OS and version are being used - missing
# 10  
Old 11-29-2014
Quote:
Originally Posted by Scrutinizer
Show
  • a representative sample of input - check
  • desired output - missing
  • attempts at a solution - check
  • specify what OS and version are being used - missing
Thank you for the pointers. Desired output ;
Code:
why?
why?
.
n

I am temporarily using slackware64 14.
n is the number of line numbers in test3.txt
# 11  
Old 11-29-2014
Try
Code:
printf %s `sed -n "$count p" test1.txt`

This should work. Still it would make sense to adopt some programming, say, standards:
Use $(...) instead of deprecated `...`
Use ${...} to separate variable names from its environment/context
Use "..." for strings like format or variables with spaces. So above would become
Code:
printf "%s" $(sed -n "${count} p" test1.txt)

# 12  
Old 11-29-2014
Then:
Code:
printf "%s" "$(sed -n "${count} p" test1.txt)"

--
Quote:
Originally Posted by y33t
Thank you for the pointers. Desired output ;
Code:
why?
why?
.
n

I am temporarily using slackware64 14.
n is the number of line numbers in test3.txt
That is the screen output. Wat is the desired output in test2.txt ?
Last edited by Scrutinizer; 11-29-2014 at 08:03 AM..
# 13  
Old 11-29-2014
Quote:
Originally Posted by Scrutinizer
Then:
Code:
printf "%s" "$(sed -n "${count} p" test1.txt)"

--

That is the screen output. Wat is the desired output in test2.txt ?
Output can be found in the attachment. I also noticed that adding ;
Code:
> test2.txt

to the end of you excpression ;
Code:
printf "%s" "$(sed -n "${count} p" test1.txt)" > test2.txt

results in an empty test2.txt.

Desired output of test2.txt is count'th line of test3 file. There will always be one line at test2.txt and it will change at each iteration.
output.txt (1.9 KB) 
# 14  
Old 11-29-2014
The output file would be empty because the script is continually overwriting the output file because of the > redirection every time it goes through the loop.

--

If we combine the recommendations in this thread, we end up with something like this:
Code:
count=1
while read item
do
  printf "%s" "$(sed -n "${count} p" test1.txt)"
  count=$((count+1))
  echo "why?"
done < test3.txt > test2.txt

Which produces:
Code:
1154why?
1155why?
1151why?
1157why?
1159why?
1163why?
1156why?
1154why?
.....

In test2.txt. Although I still do not understand what it is that you are trying to achieve...

--
The same could be achieved with this:
Code:
while read item
do
  IFS= read -r line <&3
  printf "%swhy?\n" "$line"
done < test3.txt 3< test1.txt > test2.txt

Which would be a lot quicker and also more efficient..
Last edited by Scrutinizer; 11-29-2014 at 09:25 AM..
This User Gave Thanks to Scrutinizer For This Post:
y33t
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