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Removing date field from the string

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# 1  
Old 11-23-2014
Removing date field from the string
Hii
I am trying to remove the date field from the following string.
Code:
ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT

. My output should be
Code:
ODS_EPP_COVRG_STN_DETL_FILE.TXT

I tried couple of things:
Code:
echo ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT|sed 's/_[0-9]*\.[0-9]*//g'

I am getting:
Code:
ODS_EPP_COVRG_STN_DETL_FILETXT

but i need
Code:
ODS_EPP_COVRG_STN_DETL_FILE.TXT



Thanks for your help
Last edited by Scrutinizer; 11-23-2014 at 07:30 PM.. Reason: code tags
# 2  
Old 11-23-2014
A minor modification to your code is all that is required...
Code:
echo ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT | sed 's/_[0-9]*\.[0-9]*/\./g'

# 3  
Old 11-23-2014
Or:
Code:
sed 's/_[0-9]*\././g'

or

Code:
s=ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT
echo "${s%_*.TXT}.TXT"

# 4  
Old 11-24-2014
Hello skatpally,

Following may help too in same.

Code:
echo "ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT" | awk -F"_[0-9]+" '{print $1 $2}'

Output will be as follows.
Code:
ODS_EPP_COVRG_STN_DETL_FILE.TXT

Thanks,
R. Singh
# 5  
Old 11-26-2014
You could use variable substitution in the shell too to save the cost of awk, but if the above works and you're not in a large loop then you may be happy already.



Robin
# 6  
Old 11-26-2014
Quote:
Originally Posted by rbatte1
You could use variable substitution in the shell too to save the cost of awk, but if the above works and you're not in a large loop then you may be happy already.


Robin
Is there a better way than?
Code:
string=ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT
echo ${string/_[0-9]*/.TXT}

Output:
Code:
ODS_EPP_COVRG_STN_DETL_FILE.TXT

hth
This User Gave Thanks to sea For This Post:
rbatte1
# 7  
Old 11-26-2014
Even older, works on ksh, too:
Code:
string=ODS_EPP_COVRG_STN_DETL_FILE_10032014.TXT
echo ${string%_[0-9]*}.TXT
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