Shell Programming and Scripting

I want to find all bash scripts on my system.
What I have so far is this:

Code:

find / -type f \( -perm -u=x -o -perm -g=x -o -perm -o=x \) | xargs -I{}  head -1 {} |grep bash

This will find all executables, read the first line and diplay it, if it contains "bash". Almost done, but I also need the filename and path of the bash script.

Any ideas?

Environment is AIX / ksh.

I'm looking for bash scripts only.

Perhaps something like :

Code:

find / -type f -name '*.sh' -exec head -1 {} /dev/null \;  | awk '/bash/ { print file } { file = $0 } '

Thanks, but do bash scripts necessarily end with .sh ?

What I came up with by now is:

Code:

find / -type f \( -perm -u=x -o -perm -g=x -o -perm -o=x \)  -exec grep "^#!.*/bash" {} /dev/null \;|tee bashfiles

that also makes use of your trick with the appended /dev/null.

My 2 cents:
I would test that files are ascii and not binary before using a grep... Peasant's solution avoids the problem since I dont know any binary executable name finishing with a suffix .sh ... only as you have pointed the use of a suffix is up to you and many script may have no suffixes...

Personally, I would remove the clause stating that the files have to end .sh This is not necessarily the case. There will be many scripts on your server that may be supplied code that may not have this suffix. Unlike Windows, the suffix is not important, so you cannot be sure that all scripts will have it.

The checking for executable permissions is also flawed as scripts can be sourced (i.e. read into) the current shell and do not need to be executable, just readable.


I hope that this helps,
Robin