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awk regex expression works in AIX but not in Linux

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Top Forums Shell Programming and Scripting awk regex expression works in AIX but not in Linux
# 8  
Old 07-28-2014
Quote:
Originally Posted by kamlesh_pradhan
. . .
But is there any other way to handle interval expression so that it will work in my AIX and Linux version both.
. . .
Try [A-Z][A-Z][A-Z]
# 9  
Old 07-28-2014
Thanks RudiC, Corona,

Thanks in2nix4life solution is only and simplest solution i got for this after many googling.


Summary for others to help in future.

Simplest solution is to detect OS and Run the regex statement accordingly

Code:
case "`uname -s`" in 
	"AIX")
		echo -e "Sun 12 Jul BST 2014\nSun 12 Jul 2014\nSun 12 Jul IS 2014" | awk  '/(Sun)+( 12)+( Jul )+([A-Z]{3} )?(2014)/{print;}'
		;;
	"Linux")
		echo -e "Sun 12 Jul BST 2014\nSun 12 Jul 2014\nSun 12 Jul IS 2014" | awk --re-interval '/(Sun)+( 12)+( Jul )+([A-Z]{3} )?(2014)/{print;}'
		;;
	*)
		echo "Unidenfied Operating System"
		;;
esac


Rudic Solution will be best in case there are not many old scripts which uses interval expression.
I am using Rudic Solution by the way. Smilie
Code:
[A-Z][A-Z][A-Z]
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