Shell Programming and Scripting

Hi all,

Thank you very much for your prompt responses.
I got some solution in the net its working fine in my desktop(windows 2000) with cygwin, but its giving bailing error in my server(Sun OS 5.8).
Could any one of you help me to solve the problem, the code is below.


#!/bin/ksh

dte='2003-06-11'

eval $(echo "${dte}" | awk -F- '{printf("year=%s month=%s day=%s\n", $1, $2, $3)}')

echo "year->[${year}] month->[${month}] day->[${day}]"

cal "${month}" "${year}" | awk -v day="${day}" '
FNR > 2 {
for(i=1; i <= NF; i++)
if ( $i == day) {
#printf("day->[%d] row->[%d]\n", $i, FNR-2)
printf("%d\n", (NF == 7 || FNR!=3) ? i-1 : i+(6-NF))
exit
}
}
'


Thanks in Advance
Rinku

use 'nawk' instead of 'awk' on Solaris.

thanks Perderabo....datecalc is the real answer to all date manipulations....

I wonder : Is there a way in a KSH shell what the yesterdays last business day is:
so for instance monday 03112008 (ddmmyyyy) should be give 31102008.
I've search this site but couldn't found something. Did also tried with Julians Day

I'm using AIX 5.2.0 with KSH shell pls give me a hand

Code:

$ cat yesterbusinessday
#! /usr/bin/ksh

alias datecalc=./datecalc
echo "Enter year month day"
read year month day

if (($(datecalc -d $year $month $day) == 1)) ; then
        offset=3
else
        offset=1
fi
datecalc -j $(($(datecalc -j $year $month $day) - offset))
exit 0
$ ./yesterbusinessday
Enter year month day
2008 11 3
2008 10 31
$ ./yesterbusinessday
Enter year month day
2008 10 31
2008 10 30
$

thx Perderabo for the fast reply ,

but i got a problem with the
# ./yesterbusinessday
+ alias datecalc=./datecalc
+ echo Enter year month day
Enter year month day
+ read year month day
2008 11 3
+ ./datecalc -d 2008 11 3
./yesterbusinessday[7]: ./datecalc: not found.
+ (( == 1 ))
./yesterbusinessday[7]: == 1: 0403-057 Syntax error

Sorry i'm new

I don't have an AIX ksh to test so I can't help you there. As for datecalc, the second post in this thread links to it.