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BASH Script, Watchuser

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# 1  
Old 09-25-2013
BASH Script, Watchuser
I am trying to write a BASH script to be able to tell me the following for any given user. I.e., I would like to be able to be prompted to type in a users name in order to get the info below.

Code:
User           Time logged on in seconds
User pts/0    86242

Last edited by Don Cragun; 09-26-2013 at 10:40 PM.. Reason: Use CODE tags...
# 2  
Old 09-26-2013
FYI, there are lots of people in these forums who will be willing to help you if you just show what you've already tried and ask a specific question.
Nobody here will do your job for you.
That being said, let me give you a couple of hints where you could start:
1) In the example
Quote:
User Time logged on in seconds
User pts/0 86242
The 2nd field, indicated above as Time, I think it should be Terminal, because that's what a pts/0 is (see the line below the heading).
2) Do you really want to know the logged on time in seconds? If so, what for? Isn't the actual time (hh:mm) enough?
3) In the case that the time in the hh:mm is good, do you like the following output or still prefer the table format? (Either way, the command that was executed should give you a clue as to what you should include in your script):
Code:
gacanepa@Gabriel-PC ~ $ who | awk '{print "User: "$1 " - Terminal: "$2 " - Login @: " $3" "$4}'
User: gacanepa - Terminal: tty8 - Login @: 2013-09-25 19:58
User: gacanepa - Terminal: pts/0 - Login @: 2013-09-25 20:02
User: gacanepa - Terminal: pts/1 - Login @: 2013-09-25 20:14

Give it a try and get back to us if you have any questions afterwards.
# 3  
Old 09-26-2013
Here is what I came up with. I am missing something, I am not sure what it is.

Code:
#!/bin/bash
#watchuser
case $1 in "0"
NOW=$(%s)
USR=$(who | awk {print "/user1|user2|user3|user4|user5/ "$1" Terminal: "$2 "  | grep $U)
USER1='/home/Alice | grep 'Alice' | cut -d -f2 | awk 'NR==1''
USER2='/home/Bob | grep 'Bob' | cut -d -f2 | awk 'NR==1''
USER3='/home/Mike | grep 'Mike' | cut -d -f2 | awk 'NR==1''
USER4='/home/Bill | grep 'Bill' | cut -d -f2 | awk 'NR==1''
USER5='/home/ec2-user | grep 'ec2-user' | cut -d -f2 | awk 'NR==1''
USRDATE=$(echo $USR | cut -d":" -f2)
(( USRDATE = $(date --date ""$USRDATE" +%s) / 86400 ))
(( NOW = NOW / 86400 )) (( DAYS = NOW - USRDATE ))
echo

I am getting this error when attempting to run this.

Code:
./watchuser: line 3: syntax error near unexpected token `newline'
./watchuser: line 3: `case $1 in "0"'

Last edited by Don Cragun; 09-26-2013 at 09:40 PM.. Reason: Added CODE tags.
# 4  
Old 09-26-2013
Quite simple, your case statement is wrong/incomplete..

Code:
case "$1" in
"opt1")  commands ;;
esac

You then set variables, and variables within a subshell.

What do you want to do?
-----
EDIT:

Code:
#!/bin/bash
#watchuser
for User in $(cd /home;ls --hide=lost+found);do
    echo "$User online since:"
    who|grep $User|grep pts|awk '{print $3" "$4" "$5}'
done

hth
Last edited by sea; 09-26-2013 at 09:14 PM..
# 5  
Old 09-26-2013
I am trying to be able to run an output that asks me the usersname and then when I input it, it will output the following:

Code:
User         Time logged on in seconds
User pts/0 86242

Last edited by Don Cragun; 09-26-2013 at 10:42 PM.. Reason: Add CODE tags
# 6  
Old 09-26-2013
reload the page, i had edited it Smilie
It doesnt solve it, but it should get you get started.

EDIT:
You can 'read' users input by:
Code:
read -p "Enter your name: " buffer
echo "Your name is $buffer!"

However, you might prefer select..
Code:
select User in $(cd /home;/ls --hide=lost+found);do echo $User;break;done

# 7  
Old 09-26-2013
How about if I want to have an output of when I type:
Filename username
Code:
User Time logged on in seconds
Mike pts/0 86242
Mike pts/1 8422
Mike pts/2 8422

Last edited by Don Cragun; 09-26-2013 at 10:42 PM.. Reason: Change FONT and SIZE tags to CODE tags.
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