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Mpstat script output

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# 1  
Old 08-23-2013
Mpstat script output
I have a script which runs the mpstat and prints the output in a file. In order capture highest cpu ususage from the generated output file,
have to manually tail the output file and need to grab which cpu has highest value (which is very annoying)

Is there a way we can automate that process of getting highest cpu usuage.

main script :
Code:
root@UTC # less mympstat.ksh
#!/bin/ksh
PATH=/usr/bin:/usr/sbin:$PATH
export PATH
if [ "$1" != "" ] ;then
  [ $1 -gt 0 ] && TIME=$1
else
  TIME=1
fi
LOG_BASE=${LOG_BASE:-/rit/logs/}
HOST=`hostname`
[ -d $LOG_BASE/cap ] || mkdir -p $LOG_BASE/cap
if [ ! -f $LOG_BASE/cap/mpstat_${HOST}_`date '+%Y%m%d'`.csv ];then
  echo "Date Time,CPU ID,User,System,Wait,CPU_Use" \
> $LOG_BASE/cap/mpstat_${HOST}_`date '+%Y%m%d'`.csv
fi
mpstat $TIME | while read r
do
  echo "`date '+%Y/%m/%d %H:%M:%S'` $r" |nawk '$3 !~ /CPU/ \
{printf \
  "%s %s,%d,%d,%d,%d,%d\n", \
  $1,$2,$3,$15,$16,$17,100-$18 \
}' >> $LOG_BASE/cap/mpstat_${HOST}_`date '+%Y%m%d'`.csv
done

when we tail the output file we get :
Code:
root@UTC # tail  -f /rit/logs/cap/mpstat_UTC_20130823.csv
2013/08/23 09:21:14,0,2,2,0,4
2013/08/23 09:21:14,1,0,0,0,0
2013/08/23 09:21:14,2,1,2,0,3
2013/08/23 09:21:14,3,0,1,0,1
2013/08/23 09:21:14,4,0,1,0,1
2013/08/23 09:21:14,5,1,1,0,2
2013/08/23 09:21:14,6,0,0,0,0
2013/08/23 09:21:14,7,0,1,0,1

2013/08/23 09:21:15,0,2,2,0,3
2013/08/23 09:21:15,1,0,0,0,2
2013/08/23 09:21:15,2,1,2,0,1
2013/08/23 09:21:15,3,0,1,0,6
2013/08/23 09:21:15,4,0,1,0,11
2013/08/23 09:21:15,5,1,1,0,23
2013/08/23 09:21:15,6,0,0,0,0
2013/08/23 09:21:15,7,0,1,0,11

from the above output, i need to manually look for highest cpu usuage ie (last column value) from the second set say 23 and note down its cpu ie, 5

I need to capture this values after every 10 secs from the output file (tail command)

expected output : read the mpstat_UTC_20130823.csv from a another script and calculate the highest cpu usuage and number for every 10 sec and then
just display that line saying

Code:
highest cpu usuage is : 2013/08/23 09:21:14,0,2,2,0,4
highest cpu usuage is : 2013/08/23 09:21:14,5,1,1,0,23

# 2  
Old 08-23-2013
Does this help?

Code:
awk -F"," '{if($NF>a[$1]) {a[$1]=$NF}} END{for(i in a) {print "highest cpu usage is : "i,a[i]}}' /rit/logs/cap/mpstat_UTC_20130823.csv

# 3  
Old 08-23-2013
Thanks krishmaths for quick response.

your awk command prints only last column value but i need to have cpu number(column value next to date field) + last column value in the output

Can you please show how to print that column as well.

---------- Post updated at 06:07 AM ---------- Previous update was at 06:06 AM ----------

Thanks krishmaths for quick response.

your awk command prints only last column value but i need to have cpu number(column value next to date field) + last column value in the output

Can you please show how to print that column as well.
# 4  
Old 08-23-2013
To print the entire line:
Code:
awk -F"," '{if($NF>a[$1]) {a[$1]=$NF;b[$1]=$0}} END{for(i in a) {print "highest cpu usage is : "b[i]}}'  /rit/logs/cap/mpstat_UTC_20130823.csv

To print only the second column:
Code:
awk -F"," '{if($NF>a[$1]) {a[$1]=$NF;b[$1]=$2}} END{for(i in a) {print "highest cpu usage is : "i,b[i]}}'  /rit/logs/cap/mpstat_UTC_20130823.csv

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