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NR awk problem on Ubuntu

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# 1  
Old 07-12-2013
NR awk problem on Ubuntu
Code:
awk 'NR> 92239 && NR<= 92279' /usr/appplications/access.log

is there a reason why the above command isn't working on kubuntu?

when i run it, i get nothing back. just the prompt. i should see the lines

OS:
Code:
3.8.0-19-generic #30-Ubuntu SMP

and yes, there are over 92279 lines in the log. i'm befuddled. any help here is appreciated.
# 2  
Old 07-12-2013
Seems good to me. Did you try parentheses around the inequatons?
This User Gave Thanks to RudiC For This Post:
SkySmart
# 3  
Old 07-12-2013
not sure how or where to put the parentheses.
# 4  
Old 07-12-2013
Try FNR as well, you have GNU awk (gawk). The parens go around the statement to be evaluated as a boolean.

Code:
'(FNR>111 && FNR<113) {print}' filename

This User Gave Thanks to jim mcnamara For This Post:
SkySmart
# 5  
Old 07-12-2013
It won't print anything if /usr/appplications/access.log has got less than 92239 lines.
This User Gave Thanks to MadeInGermany For This Post:
SkySmart
# 6  
Old 07-12-2013
I think Ubuntu uses mawk by default, actually.
This User Gave Thanks to Corona688 For This Post:
SkySmart
# 7  
Old 07-12-2013
Quote:
Originally Posted by SkySmart
Code:
awk 'NR> 92239 && NR<= 92279' /usr/appplications/access.log

is there a reason why the above command isn't working on kubuntu?

when i run it, i get nothing back. just the prompt. i should see the lines
I also do not see any problem with that awk script.

For diagnostic purposes, does the following command produce the expected output?
Code:
sed -n '92240,92279p; 92279q' /usr/appplications/access.log

Regards,
Alister
This User Gave Thanks to alister For This Post:
SkySmart
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