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awk if else problem

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# 1  
Old 06-24-2013
awk if else problem
Hi,

I am trying to put if else on some field of a file but not getting it where to put it.

Code:
find . -name "*" -ctime -6 | xargs cat | grep -E -v ^fileName\|^\([0-9]\) | awk -v DATE="${CURR_DATE}" -v DATE_LOG="$DATE_SYS" -v IN="" '
        BEGIN {
                FS = ";"
                OFS = ";"
                CONVFMT = "%.9g"
                OFMT = "%.9g"
        }
         {
           if(substr($0,5,6)=='NAN' {IN=1}
           else if {substr($0,5,6)=='NON' {IN=2}
         }

        {
                clef = "2-PARSING_ERROR;" DATE ";" DATE_LOG ";"
                substr ( $0, 12, 8) ";" IN ";NS;NS;" $3
                tab[clef]++
        }
        END {
                for (clef in tab)
                {
                        print tab[clef],clef
                }
        }
'

I am trying to put the red color block but not getting where to put and the right way.

Please help.

Thanks and Regards

Abhinav
# 2  
Old 06-24-2013
1. Use double quotes.
2. Parenthesis after if keyword does not close (same with else-if)
Code:
if (substr($0, 5, 6) == "NAN")

# 3  
Old 06-24-2013
Thanks for the reply but didnot help..

Code:
find . -name "*" -ctime -6 | xargs cat | grep -E -v ^fileName\|^\([0-9]\) | awk -v DATE="${CURR_DATE}" -v DATE_LOG="$DATE_SYS" -v IN="" '
        BEGIN {
                FS = ";"
                OFS = ";"
                CONVFMT = "%.9g"
                OFMT = "%.9g"
        }
        {
          if(substr($0,5,6)=="NAN") {IN=1}
          else {IN=2}
       }

..

It didnot work syntax error

awk: syntax error Context is:
Code:
>>>     GIN{FS=";";OFS=";";CONVFMT="%.9g";OFMT="%.9g"}(if       <<<

Am I putting it in a wrong way?
Moderator's Comments:
Mod Comment Please also use CODE tags when showing diagnostic output.
Last edited by Don Cragun; 06-24-2013 at 05:11 AM.. Reason: Add missing CODE tags.
# 4  
Old 06-24-2013
What OS are you using?
# 5  
Old 06-24-2013
Quote:
Originally Posted by abhi1988sri
Thanks for the reply but didnot help..

Code:
find . -name "*" -ctime -6 | xargs cat | grep -E -v ^fileName\|^\([0-9]\) | awk -v DATE="${CURR_DATE}" -v DATE_LOG="$DATE_SYS" -v IN="" '
        BEGIN {
                FS = ";"
                OFS = ";"
                CONVFMT = "%.9g"
                OFMT = "%.9g"
        }
        {
          if(substr($0,5,6)=="NAN") {IN=1}
          else {IN=2}
       }

..

It didnot work syntax error

awk: syntax error Context is:
Code:
>>>     GIN{FS=";";OFS=";";CONVFMT="%.9g";OFMT="%.9g"}(if       <<<

Am I putting it in a wrong way?
The code you included shows a an open brace before the if that isn't working; but the awk syntax error diagnostic shows an open parenthesis there. If you don't show us code that matches the diagnostics, we can't help much.

Also note that a 6 character substring (substr($0,5,6)) is never going to match a three character string ("NAN") unless $0 only contains 7 characters ending with "NAN".
# 6  
Old 06-24-2013
SunOS 5.10

But does it have to do with OS? I think I am putting it in a wrong way.
# 7  
Old 06-24-2013
Quote:
Originally Posted by abhi1988sri
SunOS 5.10

But does it have to do with OS? I think I am putting it in a wrong way.
When using Solaris systems and you are writing new awk scripts, you should use /usr/xpg4/bin/awk, /usr/xpg6/bin/awk, or nawk, instead of /bin/awk. The default /bin/awk on Solaris systems is there for compatibility with ancient awk scripts; not for new code.
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