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06-19-2013

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How to Print between ?

Hi All.

I want print log file.
I try :

Code:

cat filename |nawk  -F" " '{print $2,$3}'

but notwork.
Please Help me..

Code:

201922.Batch.batchbl.28528.f7728.AddVchr.S201306192014336016.872.ASS68848350.20033.20033: Front-end: Queue is full.KPI460.ASS68848350
201922.Offline.GWGW.23767.f7728.InqrSubrStat.S201306192019225009.1.ASS51546342.20033.20033: Front-end: Queue is full.KPI460.ASS51546342
201922.Offline.Offlinesb.27032.f7728.RqstSos.S201306192016486011.27.ASS51104165.20033.20033: Front-end: Queue is full.KPI460.ASS51104165
201922.Offline.Offlinesb.8860.f7728.RqstSos.S201306192016346009.33.ASD11275251.20033.20033: Front-end: Queue is full.KPI470.ASD11275251
201923.Offline.Offlinesb.24294.f7728.DoSnglSmapGetSubrSrvc.S201306192019227014.1.20033.20033: Front-end: Queue is full.KPI470.
201923.Offline.GWGW.24200.f7728.AddVchr.S201306192019227013.1.ASS36476547.20033.20033: Front-end: Queue is full.KPI470.ASS36476547
201923.Offline.Offlinesb.14206.f7728.RqstSos.S201306191846018012.1034.ASS50154989.20033.20033: Front-end: Queue is full.KPI460
201923.Offline.bltux.24730.f7728.InqrByAcctList.S201306192019238005.1.ASS88128068.20033.20033: Front-end: Queue is full.KPI460.ASS88128068
201923.Batch.batchbl.17153.f7728.AddVchr.S201306192015096008.832.ASS51527430.20033.20033: Front-end: Queue is full.KPI480.ASS51527430
201923.Offline.Offlinesb.24860.f7728.InqrPrpdWithMtplPckt.S201306192019236007.1.ASS46809394.20033.20033: Front-end: Queue is full.KPI460.ASS46809394
201923.Offline.Offlinesb.24937.f7728.InqrPrpdWithMtplPckt.S201306192019235008.1.ASS81208751.20033.20033: Front-end: Queue is full.KPI480

I want output

Code:

Front-end: Queue is full.KPI460
Front-end: Queue is full.KPI460
Front-end: Queue is full.KPI460
Front-end: Queue is full.KPI470
Front-end: Queue is full.KPI470
Front-end: Queue is full.KPI470
Front-end: Queue is full.KPI460
Front-end: Queue is full.KPI460
Front-end: Queue is full.KPI480
Front-end: Queue is full.KPI460
Front-end: Queue is full.KPI480

Thank You

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06-19-2013

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Try the cut command:-

Code:

cut -f2-3 -d " " filename

This should give you fields 2 to 3 from your file based on a space separator. If it's still not doing the right thing, are you sure that the gap in the records is a space?

Robin

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06-19-2013

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Code:

nawk '{gsub(/.*[0-9]: |\.$|\.A.*/,x)}1' file

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Try:

Code:

sed 's/[^:]*: \([^.]*\.[^.]*\).*/\1/' file

-or-

Code:

awk -F': ' '{split($3,F,/\./); print $2 FS F[1]"."F[2]}' file

Last edited by Scrutinizer; 06-19-2013 at 12:08 PM..

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06-20-2013

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Answer

Hello,

Could you please use the following code and try the same.
Let us assume te2 is the file which have the data as mentioned by you in thread above.

code:

Code:

 
$ awk -F "20033.20033:" '{print$2}' te2 | awk -F. '{print$1 $2}'
 
 
Front-end: Queue is fullKPI460
Front-end: Queue is fullKPI460
Front-end: Queue is fullKPI460
Front-end: Queue is fullKPI470
Front-end: Queue is fullKPI470
Front-end: Queue is fullKPI470
Front-end: Queue is fullKPI460
Front-end: Queue is fullKPI460
Front-end: Queue is fullKPI480
Front-end: Queue is fullKPI460
Front-end: Queue is fullKPI480
$

Thanks,
R. Singh

Last edited by Scrutinizer; 06-20-2013 at 06:47 AM.. Reason: icode tags to code tags

RavinderSingh13

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