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General question about passing variables among shell scripts

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# 1  
Old 05-09-2013
General question about passing variables among shell scripts
So this is something I've been wondering how to do for a while. Suppose I have two shell scripts a.sh and b.sh

script a does some function and outputs to a varable $x . I would then like to take $x into the second function, b.sh, and do a function on it and create some output. So how do you pass variables into a shell script?
# 2  
Old 05-10-2013
Quote:
So how do you pass variables into a shell script?
You pass variables from a.sh to b.sh by adding the variable after the script name, such as b.sh "$x". You receive variables in b.sh by using $1 for the first variable passed, $2 for the second, etc. Here is an example you can look at that I think makes it clearer:
Code:
$ cat a.sh
x=`date`
echo x in a.sh: $x
echo Passing x variable to b.sh script
b.sh "$x"

Code:
$ cat b.sh
echo Entering b.sh script
x="$1"
echo x in b.sh: $x
echo About to do function on x variable
y=`echo $x | cut -d " " -f 1`
echo "y (first field of x): $y"

Code:
$ ./a.sh
x in a.sh: Thu May 9 20:38:20 PDT 2013
Passing x variable to b.sh script
Entering b.sh script
x in b.sh: Thu May 9 20:38:20 PDT 2013
About to do function on x variable
y (first field of x): Thu

Note that the variable was passed as "$x" instead of $x, because without the quotes $1 would have just been "Thu".
These 2 Users Gave Thanks to hanson44 For This Post:
oompiebmf viored
# 3  
Old 05-10-2013
You can also make use of export command Smilie

a.sh
Code:
#!/bin/sh
echo "Testing 1st script"
x="Came from a.sh"
export $x
b.sh

b.sh
Code:
echo "Testing 2nd script"
echo $x
x=$x"Added at b.sh"
echo $x

This will be useful when you have to deal with more number of variables Smilie
These 2 Users Gave Thanks to PikK45 For This Post:
oompiebmf viored
# 4  
Old 05-10-2013
Wow, you guys are the best. I couldn't have asked for a better explanation. This is going to make so much of my work cleaner and easier. Thank you.
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