Shell Programming and Scripting

This is basically a copy of the script

Code:

SHOW="$2"

create-new(){
		mkdir "$bar/$SHOW"
		sed "36a\mv -v $foo/"$SHOW"\ $bar/$SHOW/" test2.sh > test3.sh
}

case "$1" in
        create)
                create-new
                ;;
        remote)
                remove
                ;;
esac

Thanks. What are the contents of test2.sh and what is the expected contents of test3.sh after sed runs?

If what you are trying to do is to create a directory and create a script (test3.sh) that is a copy of another script (test2.sh) with an mv command added after line 36 then I think the following does what you want. You haven't said what shell you're trying to use for this script, so I'm assuming a standards conforming shell such as ksh or bash. (I used ksh while I was testing this script.) Assuming that is correct, there are a couple of problems:Anyway, does this do what you're trying to do?

Code:

#!/bin/ksh
bar=to #Added because the script needs a value for bar
foo=from #Added because the script needs a value for foo
me=${0##*/} #Added for use in the usage message
SHOW="$2"

create_new(){
        mkdir "$bar/$SHOW"
        ed -s test2.sh <<-EOF
                36a
                mv -v "$foo/$SHOW" "$bar/$SHOW/"
                .
                w test3.sh
        EOF
}

case "$1" in
        (create)
                create_new ;;
        (remote)
                remove ;;
        (*)     printf "Usage:\t%s create file\n\t%s remove Who Knows What\n" \
                        "$me" "$me" ;;
esac

If not, you're going to have to actually show us exactly what you want to appear in test3.sh rather than showing us the commands that you're using to create a test3.sh that does not contain what you want.

I also note that your script has a case "remote" that calls the undefined function "remove". I assume one of these is misspelled, but since you haven't given us any indication of what should happen when $1 is not "create", I left it as is.

You are telling us that (unquoted) $foo and $bar are being expanded, while (quoted) $SHOW is not.
Is the mkdir one line above working correctly, then?
Why don't you post an execution log with the -x option set?

well i've managed to get it working now.

I took out the "" which was wrapped around $SHOW within sed

The only thing i have now is that when trying to run the test3.sh it fails due to the spaces as the file system uses "\" at the end of words with spaces.

Probably best to start a new thread to solve this other interesting problem. Include the input, expected output, and what you have tried, using code tags.