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Pattern matching notation

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# 8  
Old 03-29-2013
Thanks, I'll test it later, i'm on holiday, i 'll come back at april 3.

Have a nice week-end.
# 9  
Old 03-29-2013
Like Hanson44 notes, you need curly brackets around the shell variable, because the underscore can be part of the variable name. Also, the pattern needs to be quoted for use with -name. For a single pattern try this:
Code:
find /usr -name "${type}_log*.log.${date}.*"

--
[????????] is equivalent to [?] and \? and this means a single actual question mark.
Last edited by Scrutinizer; 04-02-2013 at 12:52 PM..
# 10  
Old 03-29-2013
As we do not know what to discriminate against, i.e. what to exclude, I think a simple * would do:
$type*.log.$date.*
# 11  
Old 03-29-2013
I know it seems like it might work, but I don't think it works:
Code:
$ cat temp.sh
touch exploitation_ora.log.2013-03-28.001
touch server.log.2013-03-28.tar.gz

date=2013-03-28
instance=ora

for type in exploitation server; do
  echo Looking just for type = $type
  find . -name "${type}_log*.log.${date}.*" -print
done

Code:
$ ./temp.sh
Looking just for type = exploitation
Looking just for type = server

Might not it be better to let the poster test the previous solution that seems to work fine, instead of confusing the situation with other possible solutions? The thread will still be here April 3rd. Smilie
# 12  
Old 03-29-2013
@hanson44: I used the OP's specification in the first post and then that should be
Code:
touch exploitation_log_ora.log.2013-03-28.001
touch server_log.log.2013-03-28.tar.gz

I am not trying to confuse matters but the OP did ask for a unified pattern.
# 13  
Old 03-29-2013
As almost usual, specifications / samples in posts #1 and #6 are contradictory if not mutually exclusive unless we assume a variable called type_log:
post #1:
Code:
$type_log_$instance.log.$date.001
$type_log.log.$date.tar.gz

post #6:
Code:
exploitation_ora.log.2013-03-28.001
server.log.2013-03-28.tar.gz

@hanson44: As there's no _log in the filenames taken from post #6, that find won't work, of course. If you use the real file names, touched above, it will:
Code:
$ for type in exploitation server; do   echo Looking just for type = $type; ls $type*.log.$date.*; done
Looking just for type = exploitation
exploitation_ora.log.2013-03-28.001
Looking just for type = server
server.log.2013-03-28.tar.gz

# 14  
Old 04-02-2013
Thanks a lot, it's working.
This site should be reimbursed by social insurance. Smilie
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