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Pattern matching notation

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# 1  
Old 03-28-2013
Pattern matching notation
Hello,

I want to simplify two commands into one.
1st command
Code:
$type_log_$instance.log.$date.001

2nd command
Code:
$type_log.log.$date.tar.gz

Into blue brackets, How do I do to replace the pattern by a blank or _$instance ?
Code:
$type_log[?_$instance].log.$date.*

Thank you.
# 2  
Old 03-28-2013
Code:
$ echo '$type_log.log.$date.001' | awk -F"." -v str='_$instance' -v OFS="." ' {$1=$1 str} 1 '
$type_log_$instance.log.$date.001

# 3  
Old 03-28-2013
It might depend on where you are using the regular expression. Each software might implement regular expressions a little different. Anyway, if I understand what you are trying to do, this might work:
Code:
$type_log(_$instance)?.log.$date.*

The ( ) defines a group, and the ? indicates the group is used 0 or 1 times, as you were trying to do.
# 4  
Old 03-28-2013
I may be poorly explained my problem.

Code:
$type[?????].log.$date.*

What should I put in place ????? equivalent to these two proposals below.
Code:
$type_$instance.log.$date.001

Code:
$type.log.$date.tar.gz

# 5  
Old 03-28-2013
Why do you use the [ ] around the ????? section?

The [ ] is normally used for [A-Z0-9] etc., to represent a single character, which you probably know.

It would help to see some actual code. Otherwise, my best guess is the previous answer I gave.
# 6  
Old 03-29-2013
Quote:
Originally Posted by hanson44
Why do you use the [ ] around the ????? section?

The [ ] is normally used for [A-Z0-9] etc., to represent a single character, which you probably know.

It would help to see some actual code. Otherwise, my best guess is the previous answer I gave.
Hello,
Thanks for your help.

Imagine i have several files with these forms :
exploitation_ora.log.2013-03-28.001
server.log.2013-03-28.tar.gz
After creating variables, i have this :
$type_$instance.log.$date.001
$type.log.$date.tar.gz

What's pattern matching notation or regular expression [????????] do i put to replace _$instance or nothing ?
Code:
$type_$instance.log.$date.001
$type          .log.$date.tar.gz
$type[????????].log.$date.*

For example, i can include this in a script.
Code:
find /usr -name $type[????????].log.$date.*

Have a nice day
# 7  
Old 03-29-2013
Thanks for explaining more.

The regular expression seems rather complex (In other words, I couldn't figure it out Smilie), so I tried a different way.

Instead of making one all-purpose, confusing pattern, I suggest to to let find use either of two patterns. See if this makes sense, and does the job:
Code:
$ cat temp.sh
touch exploitation_ora.log.2013-03-28.001
touch server.log.2013-03-28.tar.gz

date=2013-03-28
instance=ora

for type in exploitation server; do
  echo Looking just for type = $type
  find . \( -name "${type}_$instance.log.$date.*" -o \
            -name "${type}.log.$date.*" \) -print
  echo
done

echo Looking for type = exploitation OR server
find . \( -name "exploitation_$instance.log.$date.*" -o \
          -name "server.log.$date.*" \) -print

Code:
$ ./temp.sh
Looking just for type = exploitation
./exploitation_ora.log.2013-03-28.001

Looking just for type = server
./server.log.2013-03-28.tar.gz

Looking for type = exploitation OR server
./exploitation_ora.log.2013-03-28.001
./server.log.2013-03-28.tar.gz

So the final find command would be the one to use, unless there is some other complication I'm missing.
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