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replacing text in an ascii doc

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# 1  
Old 09-28-2005
replacing text in an ascii doc
What would be the best way to replace all instances of...

09/26/2005
with
20050926

There are no spaces between the the date and the preceeding and following data. example lines looks like...

snp01|NAME/OF/A/GROUP|09/26/2005081343|502

the 081343 is the time without colons.

Thank you.
# 2  
Old 09-28-2005
Code:
ruby -pe'sub(%r!(\d\d)/(\d\d)/(\d{4})!,"\\3\\1\\2")'

# 3  
Old 09-28-2005
????
Could you explain that more...

I'm using the korn shell. How would I use ruby inside a korn script.
# 4  
Old 09-28-2005
the sed command
I tried using the sed command, but it's doesn't do anything...

sed -e 's/$date/$newDate/g' $ofile > test.txt
# 5  
Old 09-28-2005
Quote:
I tried using the sed command, but it's doesn't do anything...

sed -e 's/$date/$newDate/g' $ofile > test.txt
Code:
sed -e "s#$date#$newDate#g" $ofile > test.txt

# 6  
Old 09-28-2005
...
that sed command is not working for me...

I was going to try using this to do it, but it won't pass the variable to it...

/bin/echo '%s/^/"$newDate "/g\nwq!' | ex - $ofile
# 7  
Old 09-29-2005
MySQL
Please check one again, I tried sed command suggested above works perfectly.


Here is the test:

Code:
 >more g
09/26/2005
 >echo $old_date
09/26/2005
 >echo $new_date
20050926
 >sed -e "s:$old_date:$new_date:g" g
20050926

The ex command is not working because the subsitute pattern will fail becuase of backslashes in variable itself.

rishi
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