Print a line


 
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# 1  
Old 03-06-2013
Print a line

Hi,
I have a script like below

Code:
file=/etc/hosts
n=0
while IFS= read -r line
do
echo $n
n=$((n+1))
if [ $n == 3 ]
then
        echo $line
fi
done < "$file"

=======================================
and i am getting output like below

Code:
0
1
2
127.0.0.1 localhost.localdomain localhost
3


My query is whenever i am running this script it should ask type the line which you want to print. So, please make me do it like this.


Regards,
Mastan

Last edited by Scrutinizer; 03-06-2013 at 09:05 AM.. Reason: code tags
# 2  
Old 03-06-2013
Code:
file=/etc/hosts
n=1
echo "enter which line you want to print"
read lin
while IFS= read -r line
do
if [[ $lin == $n ]];
then
echo $line
fi
n=$((n+1))
done < "$file"

# 3  
Old 03-06-2013
Assuming that this is trying to get the 3rd line of $file, you can use sed
Code:
sed -n 3p $file


Is this what you are after?



Robin
Liverpool/Blackburn
UK
# 4  
Old 03-06-2013
Get 3rd line with awk
Code:
awk NR==3 $file

This User Gave Thanks to Jotne For This Post:
# 5  
Old 03-07-2013
Hi guys,

Thanks for helping. It is working fine.

Regards,
Mastan
# 6  
Old 03-07-2013
With the regards to the OP's original script:
Code:
if [ $n -eq 3 ]; then printf "%s\n" "$line" fi

# 7  
Old 03-07-2013
Code:
$ read -p "Enter line to read: " lNo; awk NR==$lNo /etc/hosts
Enter line to read: 3
127.0.0.1    localhost.localdomain        localhost

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