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Leading blanks

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# 1  
Old 03-01-2013
Leading blanks
Hi

Ich have a list as follows

Code:
73
5
100
45
81
4

and I would like to have an output (on screen) like that

Code:
  73
   5
100
 45
 81
  4

googled and tried a lot (printf and sed) but got no satisfactory result.

Can anyone help?

Thanks
Lazy

---------- Post updated at 06:35 PM ---------- Previous update was at 06:34 PM ----------

Hi

Of course, the leading blanks in the second list disappeared ...

Lazy
Last edited by Scrutinizer; 03-01-2013 at 03:20 PM..
# 2  
Old 03-01-2013
Please edit your text again and wrap it in CODE tags.
(The tags are at the top of the WIKI editor.)
# 3  
Old 03-01-2013
What about
Code:
$ while read tmp; do printf "%10s\n" $tmp; done < file
        73
         5
       100
        45
        81
         4

# 4  
Old 03-01-2013
Quote:
Originally Posted by lazybaer
Hi

Ich have a list as follows

73
5
100
45
81
4

and I would like to have an output (on screen) like that

Code:
  73
   5
100
 45
 81
  4

googled and tried a lot (printf and sed) but got no satisfactory result.

Can anyone help?

Thanks
Lazy

---------- Post updated at 06:35 PM ---------- Previous update was at 06:34 PM ----------

Hi

Of course, the leading blanks in the second list disappeared ...

Lazy
I added code tags to show the output I assume you want. If your list of numbers is in a file named list, the following seems to do what you want:
Code:
#!/bin/ksh
i=1
while read n
do      if [ $i -lt 3 ]
        then    printf "%4d\n" "$n"
        else    printf "%3d\n" "$n"
        fi
        i=$((i + 1))
done < list

# 5  
Old 03-01-2013
Was ich habe, ist ein ermittelter Wert

Code:
56
6
100
45

und was ich möchte, sollte so aussehen

Code:
 56
  6
100
 45

zB auf dem Bildschirm

Lazy
Last edited by Scrutinizer; 03-01-2013 at 03:28 PM.. Reason: Too many code tags
# 6  
Old 03-01-2013
English please!
And you wrapped in ICODE - CODE looks better.

---------- Post updated at 01:07 PM ---------- Previous update was at 01:01 PM ----------

Code:
printf "%3s\n" `cat file`
awk '{printf "%3s\n",$0}' file

# 7  
Old 03-01-2013
I have now the solution, thanks RudiC

Looks like that

Code:
printf "%3s" $4; echo " % xxx yyyyyyy zzzzz"

Regards
Lazy
Last edited by Scrutinizer; 03-01-2013 at 03:24 PM.. Reason: code tags
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