Date derivation


 
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# 1  
Old 02-14-2013
Date derivation

Need to get saturday's date of the previous week.

Input will be the sysdate (today's date)

Output should be previous weeks's saturday format

Your help is required extremely.

I have done all the date arthimetic calculation, but not getting the desired output. Please help

Last edited by vbe; 02-14-2013 at 12:22 PM.. Reason: rm code tags... code tags are required ofr code and data! and only code and data
# 2  
Old 02-14-2013
Quote:
Originally Posted by help_scr_seeker
I have done all the date arthimetic calculation, but not getting the desired output.
Can you show us what you tried?

Also let us know what OS and SHELL you are using:
Code:
uname -a
echo $SHELL

# 3  
Old 02-14-2013
Code:
$ uname -a
AIX cissrv67 1 6 000FBC01D900

---------- Post updated at 11:25 AM ---------- Previous update was at 11:19 AM ----------

Code:
$ echo $SHELL
/usr/bin/ksh

# 4  
Old 02-14-2013
Post what you have done so far to solve this problem...
# 5  
Old 02-14-2013
Code:
use strict;
use warnings;
use DateTime;
my $d = DateTime->now;
while ( $d->day_of_week != 6 ) {
    $d->subtract( days => 1 );
        }
        print $d->ymd;

I developed this code in perl. Unfortunately, the perl modules is not installed in the client server. So unable to use that :-(

I need some help in shell scripting.
# 6  
Old 02-14-2013
Have a look at Perderabo's thread: Date Arithmetic
# 7  
Old 02-14-2013
Quote:
Originally Posted by help_scr_seeker
Code:
use strict;
use warnings;
use DateTime;
my $d = DateTime->now;
while ( $d->day_of_week != 6 ) {
    $d->subtract( days => 1 );
        }
        print $d->ymd;

I developed this code in perl. Unfortunately, the perl modules is not installed in the client server. So unable to use that :-(

I need some help in shell scripting.
I suggest you get perl installed on the client machine as date math imho is done best in perl...
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