Arithmetric in while statement


 
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# 1  
Old 02-12-2013
Arithmetric in while statement

I am running a loop that if $a is less than 1.5 OR $b is greater than 0.7 then do certain operation until $a is great than 1.5 AND $b is less than 0.7

at the moment $a=2.4 and $b=0.7

the script is

Code:
while [[ $a -lt 1.5 || $b -gt 0.7 ]]
do
(operation that will reassign $a and $b)
if [[ $a -gt 1.5 && $b -lt 0.7 ]]
then
break
fi
done

but I get the following error

Code:
line 66: [[: 2.4: syntax error: invalid arithmetic operator (error token is ".4")
 line 66: [[: 0.701: syntax error: invalid arithmetic operator (error token is ".701")

what have I done wrong?
# 2  
Old 02-12-2013
Presumably you are using bash, which can only do integer arithmetic. Try using ksh93 instead..
# 3  
Old 02-12-2013
I am using zsh.....
# 4  
Old 02-12-2013
Are you sure? It looks like a bash error message... zsh should know floating point arithmetic, like ksh93...
# 5  
Old 02-12-2013
Code:
echo $SHELL

Code:
/sw64/bin/zsh

# 6  
Old 02-12-2013
Define the variables as floats and use parens instead of square brackets for a numeric comparison.
Code:
$ cat x
#!/bin/zsh

typeset -F a=1.4
typeset -F b=1.7

printf "START - a: %0.2f, b: %0.2f\n\n" $a $b

while (( $a < 1.5 || $b > 0.7 )); do
  (( a=$a + .1 ))
  (( b=$b - .1 ))
  printf "a: %0.2f, b: %0.2f\n" $a $b
  if (( $a > 1.5 && $b < 0.7 )); then
    break
  fi
done

exit 0
$ ./x
START - a: 1.40, b: 1.70

a: 1.50, b: 1.60
a: 1.60, b: 1.50
a: 1.70, b: 1.40
a: 1.80, b: 1.30
a: 1.90, b: 1.20
a: 2.00, b: 1.10
a: 2.10, b: 1.00
a: 2.20, b: 0.90
a: 2.30, b: 0.80
a: 2.40, b: 0.70
$


Last edited by gary_w; 02-12-2013 at 11:59 AM..
# 7  
Old 02-12-2013
Why arent you using /bin/zsh ?
Just tested, it works... I dont have a sw64 directory...
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