Parsing expect_out using regex in expect script


 
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Old 12-16-2012
Parsing expect_out using regex in expect script

Hi,

I am trying to write an expect script. Being a newbie in expect, maybee this is a silly doubt but i am stuck here.

So essentially , i want the o/p of one router command to be captured . Its something like this

Code:
Stats

Input Rx   	: 1234
Input Bytes 	: 3456

My expect script looks something like this

Code:
  1 #!/usr/bin/expect -f
  2 set prompt {>}
  3 set timeout 20
  4 set user [lindex $argv 0]
  5 set password [lindex $argv 1]
  6 spawn su $user
  7 expect "Password:"
  8 send "$password\r";
  9 send -- "ls\r"
 10 expect $prompt
 11 puts "The output is $expect_out(buffer)"
 12
 13 interact


Now, i see the complete o/p by the last statement. Not able to get the correct syntax of -re for parsing the o/p. Just want to store the variables
Input Rx and input bytes.


Any help is really appreciated.

Thanks,
ashy_g

Last edited by Scott; 12-17-2012 at 03:54 PM.. Reason: Code tags
 
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