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Shell Programming and Scripting

Replace with NA if blank is there

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# 8  
Old 12-16-2012
Code:
sed 's/\(^[^,]*\,.*\),,/\1,NA,/;s/\(^[^,]*\),,/\1,NA,/' infile

For any columns if empty, replace by NA

Code:
awk '{for (i=1;i<=NF-1;i++) if ($i=="") $i="NA"}1' FS=, OFS=,  infile

# 9  
Old 12-17-2012
Quote:
Originally Posted by rdcwayx

. . . For any columns if empty, replace by NA
Code:
awk '{for (i=1;i<=NF-1;i++) if ($i=="") $i="NA"}1' FS=, OFS=,  infile

The request was to replace ONLY $2 and/or $3. If you really want ro replace all empty fields, try
Code:
 awk '{gsub(",,",",NA,")}1' file

# 10  
Old 12-17-2012
Quote:
Originally Posted by RudiC
The request was to replace ONLY $2 and/or $3. If you really want ro replace all empty fields, try
Code:
 awk '{gsub(",,",",NA,")}1' file

In that case you would need to do that twice in this case, for example:
Code:
sed 's/,,/,NA,/; s/,,/,NA,/' file


--
There would be no need for that with perl:
Code:
perl -pe 's/,(?=,)/,NA/g' file

Last edited by Scrutinizer; 12-17-2012 at 03:34 AM..
# 11  
Old 12-17-2012
With Sed..
Code:
sed -e 's/^\([^,]*,\)\(,\)/\1NA\2/' -e 's/\([^,]*,[^,]*,\)\(,\)/\1NA\2/'  inputfile

Or a little shorter version..
Code:
sed -e 's/^\([^,]*,\),/\1NA,/' -e 's/\([^,]*,[^,]*,\),/\1NA,/' inputfile
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