Shell Programming and Scripting

Hi

I have a strange issue and hence asking for your help.

I am using a RHEL machine and the user passwords are stored inside /etc/shadow file. These are md5 encrypted passwords. I am extracting these encrypted passwords in a shell script and want to pass them to another shell script. But these passwords look like - "$1$98meo/YZ$.qOaoqb", or "$5$5gHl7rC19jx0UHTm50" - they start with $[1-9]$. Hence I am not able to transfer them correctly. Initial $1$ is getting converted into "ignoreeof". For example

Code:

script_name $1$98meo/YZ$.qOaoqb
script_name "$1$98meo/YZ$.qOaoqb"

nothing works.

In the same context

Code:

[ferrari-int] a=$1$567
[ferrari-int] echo $a
ignoreeof67

Is there any way to transfer the value to another script as an argument? I know if we escape the $, then it will work -

Code:

[ferrari-int] a=\$1\$567
[ferrari-int] echo $a
$1$567

But is it the only way?

If this escaping is the only way, then how we can replace the initial $1$ by \$1\$? What should be the sed liner?

Thanks in advance.

Try:

Code:

a='$1$567'

And you're echo-ing wrongly

Code:

echo "$a"

or better:

Code:

printf '%s\n' "$a"

Just to add, it should be:

Code:

script_name '$1$98meo/YZ$.qOaoqb'