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Shell Programming and Scripting

Filename manipulation

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# 8  
Old 10-18-2012
Thank you all for the prompt responses! I'll give all options a go. Thanks again.

Regards,

ivan

---------- Post updated at 09:23 AM ---------- Previous update was at 08:08 AM ----------

Sorry if I'm not using the appropriate tags to reply, just joined yesterday so haven't got the time to work it out yet.

@skrynesaver.. The filename is hardcoded in your perl code, how do we pass a variable with the filename instead?

@babom.. your code works fine for the sample I provided, however it seems to only work with that filename length (i.e MY_FILE_NAME)? if the filename is different, the result is incorrect.

@elixir_sinari.. is it possible to embed this in a shell script? I failed to mentioned I'm using a shell script to do this conversion. Sorry.

@itkamaraj.. I got an error 'Bad substitution' when I ran that code. Is that only for certain shell version?

Regards,

Ivan
# 9  
Old 10-18-2012
Quote:
Originally Posted by schweinshaxe
@itkamaraj.. I got an error 'Bad substitution' when I ran that code. Is that only for certain shell version?
Please get into the habit of specifying your operating system and shell versions. It will save all of us (including yourself) time that will otherwise be squandered asking for that information and providing inappropriate suggestions in its absence.

The following should work with any POSIX-compliant shell (although it wouldn't be a bad idea to quote all of those parameter expansions ... just in case):
Quote:
Originally Posted by itkamaraj
Code:
 
$ for i in *.data; do a=${i%.*};echo mv $i 0${a##*_}_${i%_*}.${i##*.}; done

Regards and welcome to the forum,
Alister
# 10  
Old 10-18-2012
Another one:

Code:
ls *.data | sed 'p;s/\(.*\)_\([0-9]*\)\(\..*$\)/\2_\1\3/' | xargs -n2 mv
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