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Want to terminate command execution when string found in the command output

 
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Old 10-10-2012
Want to terminate command execution when string found in the command output
Hi Experts,

I am very much new to linux scripting, I am currently working on reducing my manual work and hence writing a script to automate few task.

I am running below command to snmpwalk the router..

Code:
snmpwalk -v 3  -u WANDL_SU -a MD5 -A vfipmpls -x DES -X VfIpMpLs -l authPriv 182.19.96.13 |grep ae0.784

get below output..

Code:
Did not find 'MplsVpnName' in module MPLS-VPN-MIB (/usr/local/share/snmp/mibs/mib-jnx-ldp.txt)
IF-MIB::ifDescr.2500 = STRING: ae0.784
Timeout: No Response from 182.19.96.13

this command finds the string and show it in output..but when I run below command..

Code:
snmpwalk -v 3  -u WANDL_SU -a MD5 -A vfipmpls -x DES -X VfIpMpLs -l authPriv 182.19.96.13 |grep ae0.784 |awk '{print $2}'

get below output..

Code:
Did not find 'MplsVpnName' in module MPLS-VPN-MIB (/usr/local/share/snmp/mibs/mib-jnx-ldp.txt)
Timeout: No Response from 182.19.96.13
=

command is verymuch fine..but i am not getting why it shows timeout when i try to print 2 column...

also one more requirement is program should terminate once match is found and also print given column in some output file..

looking for help from the experts...

thanks in advance!!!

Regards,
Hanuamnt
Last edited by Scrutinizer; 10-10-2012 at 07:47 AM.. Reason: code tags
 
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