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remove the ".0" of a date

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# 1  
Old 09-03-2012
remove the ".0" of a date
Hi,

I want to transform a txt file to make a new one. I want to remove the ".0" of the dates only (after the time, there is ".0" that I dont need.

I.e

Code:
1480.1    1.0    1.0    2012-07-08 23:38:11.0    2012-07-08 23:40:14.0

I want to transform this line to get this new one...

Code:
1480.1    1.0    1.0    2012-07-08 23:38:11    2012-07-08 23:40:14

here's the gawk I am using


Code:
gawk -F"." '$1~/[0-9][0-9]:[0-9][0-9]:[0-9][0-9]/ { print $1 substr($2,2) } ' MKT_ESTADO_CONSUMIDOR_WEB.TXT

It's ok if I don't have other "." in the line

i.e
from this line...
Code:
1479    9    0    2012-07-06 10:58:13.0    null

I get this one

Code:
1479    9    0    2012-07-06 10:58:13    null

Last edited by Scrutinizer; 09-03-2012 at 02:05 PM.. Reason: code tags
# 2  
Old 09-03-2012
Code:
perl -lnpe ' s/(\d+:\d+:\d+)\.0/$1/g;' input_file

Thanks scrutinizer for alerting on "."
Last edited by msabhi; 09-03-2012 at 01:44 PM..
This User Gave Thanks to msabhi For This Post:
edgar.piquer
# 3  
Old 09-03-2012
Or sed:
Code:
sed 's/\(..:..:..\)\.0/\1/g' infile

(the . before the 0 should be escaped)
These 2 Users Gave Thanks to Scrutinizer For This Post:
edgar.piquer msabhi
# 4  
Old 09-03-2012
Code:
cat file_name| perl -e 's/(\d\-\d-\d\s\d:\d:\d)\.0/$1/gc'

this will give you desired output..
Last edited by Scrutinizer; 09-03-2012 at 02:05 PM.. Reason: code tags
This User Gave Thanks to replytoshishir For This Post:
edgar.piquer
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