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row separator with RS

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# 1  
Old 08-31-2012
row separator with RS
I have a file contains lines such as below:
Code:
HRS ? ? ? Pg ? 20120811 1223 19.6 GAU 1.00e-01 0.00e-01 0.00e-01 0.00e-01
TBZ ? ? ? Pg ? 20120811 1223 26.2 GAU 1.00e-01 0.00e-01 0.00e-01 0.00e-01
###             
HRS ? ? ? Pg ? 20120811 1228 52.2 GAU 1.00e-01 0.00e-01 0.00e-01 0.00e-01
###             
HRS ? ? ? Pg ? 20120811 1230 17.8 GAU 1.00e-01 0.00e-01 0.00e-01 0.00e-01
TBZ ? ? ? Pg ? 20120811 1230 22.7 GAU 1.00e-01 0.00e-01 0.00e-01 0.00e-01
BST ? ? ? Pg ? 20120811 1230 26.3 GAU 1.00e-01 0.00e-01 0.00e-01 
###

i wrote this code to separate each line which take place between "###":
Code:
awk 'BEGIN {RS="###";FS="\n";ORS=""}{print}'  in > out

now i have 3 row and i want to print row number 2 :
Code:
HRS ? ? ? Pg ? 20120811 1228 52.2 GAU 1.00e-01 0.00e-01 0.00e-01 0.00e-01

so i wrote this code :
Code:
awk 'BEGIN {RS="###";FS="\n";ORS=""}{if(NR=3) print}' in > out

but the output is as the same as input! no changes
# 2  
Old 08-31-2012
Code:
{if(NR==3) print}

This User Gave Thanks to CarloM For This Post:
saeed.soltani
# 3  
Old 09-01-2012
Oh God! Thanks a lot
# 4  
Old 09-02-2012
Quote:
i want to print row number 2 :
Quote:
if(NR==3)
This will print 3rd record, not 2nd, you realize that, right?

You can make it simpler:
Code:
awk 'NR==2' RS=###  infile

This User Gave Thanks to mirni For This Post:
saeed.soltani
# 5  
Old 09-02-2012
Yes i did, it was a writing mistake. thank you
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