Shell Programming and Scripting

Hi All,

I have a requirement to fetch logs of last 'N' days.
I am trying the following command which is working fine if it finds the date of that day in logfile.

Code:

START=`TZ="GMT+$((24*N))" date +"%Y %b %d"`

this is being used to fetch 'N'th day's date
and

Code:

awk '/'"$START"'/{p=1} /'"$NOW"'/p' <logfile.log

is being used to fetch the records from log file.

like if last 'N' day's date is 2012 Jun 17
and this date is present in file then it gives out the record from 2012 Jun 17 to NOW.

But if last 'N' day's date is 2012 Jun 17 and it is not present in log file then its giving the blank response , though there are records available for date 2012 Jun 16.

Please help me!

Thanks in advance!
Regards,
KD

Moderator's Comments:

Please view this code tag video for how to use code tags when posting code and data.

Have a look at this thread:

https://www.unix.com/shell-programmin...amps-file.html

Thanks but that is worked in cse if we kknow the exact date or timestamp.
Problem is that if that timestamo or date is not present in log file iit is giving whole file where aas it should give response as per my first post.

This should work, you don't have to give the exact timestamp:

Code:

cat file | awk -F, '{ if ($1>"2012-08-20 11:30" && $1<"2012-08-22 16:00") print }'

You are getting blank output for the logs for which last n days log is not present because you are setting p=1 only when log is present for last Nday

Use your variables directly...

Code:

awk -F, -v ST="$START" -v NW="$NOW" '{ if ($1 > ST && $1 < NW ) print }' file

But this will work only if date is in the format of yyyy mm dd