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# 8  
Old 08-05-2012
First, remove the single quotes around the occurrences of $a.
Second, what shell are you using? Depending on this, you may be able to use shell arithmetic expressions, like a=$((a+1)) in bash, otherwise you will need to take a different approach, sth. like expr that donadarsh mentioned.
# 9  
Old 08-05-2012
my mistake - '$a' shouldn't be in single quote. It will read it as one string. better use "$a".
# 10  
Old 08-05-2012
Quote:
Originally Posted by donadarsh
my mistake - '$a' shouldn't be in single quote. It will read it as one string. better use "$a".
Code:
#!/bin/bash

limite=3
a=0

while ["$a" -le "3"];
do


if ["$a" -eq "1"];
then

pru=/usr/bin/mei.txt
cat $pru | mail -s "IMEIS" mathias@wirtel.com.ar

fi




if ["$a" -eq "2"];
then

pru=/usr/bin/mei2.txt
cat $pru | mail -s "IMEIS" mathias@wirtel.com.ar

fi


a=$a+1

done


if ["$a" -eq "2"];
then

a=1

fi



the code with " but return me this
Code:
/usr/bin/imei: line 6: [0: command not found
/usr/bin/imei: line 35: [0: command not found

Last edited by Franklin52; 08-06-2012 at 03:48 AM.. Reason: Please use code tags for data and code samples
# 11  
Old 08-06-2012
Debian
Code:
#!/bin/bash

limite=3
a=0

while [ "$a" -le 3 ]; do

    if [ "$a" -eq 1 ]; then
        pru=/usr/bin/mei.txt
        cat $pru | mail -s "IMEIS" mathias@wirtel.com.ar
    fi

    if [ "$a" -eq 2 ]; then
        pru=/usr/bin/mei2.txt
        cat $pru | mail -s "IMEIS" mathias@wirtel.com.ar
    fi

    #a=$a+1
    a=`expr $a + 1`

done

if [ "$a" -eq 2 ]; then
    a=1
fi

# 12  
Old 08-06-2012
Hi,

1. remove all semi-colons they are not required in shell scripts
2. remove the single quotes around the varaibles in if conditon
i.e.
Code:
 
while [ $a -le $limite ]

the single quotes disable varaible interpolation, to use the value of the variable either use
Code:
""

double quotes or don't use quotes at all
3.
Code:
$a=$a+1

is wrong
you can write this section as
Code:
let a=a+1

(notice no spaces between
Code:
a=a+1

)
or
Code:
a=`expr $a + 1`

(notice the spaces and backticks this time)
# 13  
Old 08-06-2012
[ is command and need arguments and argument delimiters, it is not bracket like in the programming languages.
if variable is empty, then you get error if value is empty. In that case double quotes => you have always argumen even it's empty.
$a is not same as "$a" in the command line if value of the a is empty.
Code:
#!/bin/bash

limite=3
a=1

while [  "$a"  -le  "$limite"  ]   # this is okay, no problem
# or while (( a <= limite ))
do

if  [  "$a"  -eq 1 ]   # delimiters after command [ and between arguments 
# or if  (( a == 1 ))
then
    pru=/usr/bin/mei.txt
    cat $pru | mail -s "IMEIS" account@domain.com
fi

if  [ "$a"  -eq  2 ]
# or  if (( a == 2 ))
then
    pru=/usr/bin/mei2.txt
   cat $pru | mail -s "IMEIS" account@domain.com
fi
  
#$a=$a+1
((a=a+1))   # works fine in ksh and bash, but not in dash
a=$((a+1)) # posix compatible version
# or use let command, it's also builtin command, expr does not

done

if [ "$a" -eq 2 ]
# or if (( a == 2 ))
then
   a=1
fi

# 14  
Old 08-06-2012
Quote:
Originally Posted by kshji
[ is command and need arguments and argument delimiters, it is not bracket like in the programming languages.
if variable is empty, then you get error if value is empty. In that case double quotes => you have always argumen even it's empty.
$a is not same as "$a" in the command line if value of the a is empty.
Code:
#!/bin/bash

limite=3
a=1

while [  "$a"  -le  "$limite"  ]   # this is okay, no problem
# or while (( a <= limite ))
do

if  [  "$a"  -eq 1 ]   # delimiters after command [ and between arguments 
# or if  (( a == 1 ))
then
    pru=/usr/bin/mei.txt
    cat $pru | mail -s "IMEIS" account@domain.com
fi

if  [ "$a"  -eq  2 ]
# or  if (( a == 2 ))
then
    pru=/usr/bin/mei2.txt
   cat $pru | mail -s "IMEIS" account@domain.com
fi
  
#$a=$a+1
((a=a+1))   # works fine in ksh and bash, but not in dash
a=$((a+1)) # posix compatible version
# or use let command, it's also builtin command, expr does not

done

if [ "$a" -eq 2 ]
# or if (( a == 2 ))
then
   a=1
fi




thank you very much but , i have a problem

the code now is

Code:
#!/bin/bash

limite=2
a=1

while [  "$a"  -le  "$limite"  ];   # this is okay, no problem

do

if  [  "$a"  -eq "1" ];   

then
    pru=/usr/bin/mei.txt
    cat $pru | mail -s "IMEIS" account@domain.com
fi

if  [ "$a"  -eq  "2" ];

then
    pru=/usr/bin/mei2.txt
   cat $pru | mail -s "IMEIS" account@domain.com
fi


a=$((a+1)) # posix compatible version


done

if [ "$a" -eq "2" ];

then
   a=1
fi


they not have sintax error but , the send me 2 mails , the if not found , i dont know really why.
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