Shell Programming and Scripting

Code:

find . -newer <file_name> -exec ls -1ad {} \+

works fine.

Thanks!

Hi

By the way, you can't use -exec ls -lrt to sort the find output, because ls will be called for each file, so it will only sort the given file.

You should sort after the find process, maybe you could use something like find ... -printf "%T@ %p", and then use sort -n on the output.

I'm not sure whether sun find supports -printf in that way. You need to not rely on extensions when using Solaris.

You are right i forgot about those Solaris limits.

Maybe this should work then :

Code:

find  . -newer filename -exec perl -e "\$fname=\"{}\";"'$mtime=(stat($fname))[9]; printf("%ld %s\n",$mtime,$fname);' \; |
  sort -n |
  awk '{print $2}'

If perl is going to be used, there's really not much point in using find, sort, or awk. Perl can traverse directory trees, sort lists, extract fields, etc.

The following may be of interest:
http://perldoc.perl.org/File/Find.html
http://perldoc.perl.org/find2perl.html

A similar, more efficient approach to your suggestion would be to -exec stat .... GNU and solaris both provide a stat utility, but they require different options to accomplish the same task. Before calling find, the script can test the platform to choose between the two syntaxes.

Regards,
Alister

This works fine as long as you either have a small number of files OR don't care about a long list of files that isn't sorted.

Note also that you can just use "+" instead of "\+"; you need "\;" instead of just ";" because an unescaped <semicolon> is special to the shell.